Question

我正在开发一个WPF项目，我已经添加了一个TreeView。我还为TreeView创建了一个ContextMenu，如下所示：

<TreeView Name="treeView" ItemsSource="{Binding Elements}">

                <TreeView.ContextMenu>
                    <ContextMenu Name="treeViewContextMenu">
                        <MenuItem Header="First option"/>
                        <MenuItem Header="Second Option/>
                    </ContextMenu>
                </TreeView.ContextMenu>

.... </TreeView>

由于我以dinamically方式添加treeView节点，如何检测右键单击哪个节点以打开contextMenu？

希望有人可以帮助我，提前谢谢

Answer 1

假设我动态加载了我的treeview项目..

  <TreeView Name="treeView" ContextMenuClosing="treeView_ContextMenuClosing">

    <TreeView.ContextMenu>
        <ContextMenu Name="treeViewContextMenu">
            <MenuItem Header="First option"/>
                <MenuItem Header="Second Option"/>
            </ContextMenu>
     </TreeView.ContextMenu>
        <TreeViewItem Header="Hello 1"/>
        <TreeViewItem Header="Hello 2"/>
     </TreeView>

<强> MainWindow.xaml.cs

private void treeView_ContextMenuClosing(object sender, ContextMenuEventArgs e)
        {
           //Sender should let me determine who sent it from my children/parent

            var parent  = sender as TreeView;
            var children = parent.SelectedItem as TreeViewItem;
            MessageBox.Show(children.Header.ToString());
        }

如果你想知道ContextMenu 关闭/打开 时的对象，或者当MenuItem 点击时的任何事件，这取决于你。

检测右键单击的TreeView节点

1 个答案: