Question

我有一张桌子，我希望在最后一排之前得到这一行。例如

KeyboardID     KeyboardName
1                 "DELL"
2                 "HP"
3                 "Viewsonic"
4                 "Samsung"

从键盘选择max（keyboardid） - ＆gt;将获得三星

我的问题是如何获得Viewsonic键盘......

Answer 1

SELECT * 
  FROM (
  SELECT *, 
    ROW_NUMBER() OVER (ORDER BY KeyboardId DESC) AS rn
  FROM Table
) AS t
WHERE rn = 2;

或

WITH cte AS (
   SELECT *, ROW_NUMBER() OVER (ORDER BY KeyboardId DESC) AS rn
   FROM Table)
SELECT *
    FROM cte
    WHERE rn = 2;

或

SELECT TOP(1) *
  FROM (
  SELECT TOP(2) * 
      FROM Table
      ORDER BY KeyboardId DESC) AS t
  ORDER BY KeyboardId;

Answer 2

SELECT TOP 1 *
FROM Keyboard
WHERE KeyboardID < (SELECT MAX(KeyboardID) FROM Keyboard)
ORDER BY KeyboardID DESC

Answer 3

实际上这是一个面试问题。获得id：

SELECT MAX(KeyboardID) as SecondPlaceID
FROM Keyboard
WHERE KeyboardID < (SELECT MAX(KeyboardID) FROM Keyboard)

或整行：

    SELECT *
    FROM Keyboard
    WHERE KeyboardID = (SELECT MAX(KeyboardID)
                        FROM Keyboard
                        WHERE KeyboardID < 
                              (SELECT MAX(KeyboardID) FROM Keyboard))

Answer 4

Declare @MaxID Int
Select @MaxID = max(KeyboardID) from tblFacts

Select top 1 * from tblFacts where KeyBoardID < @MaxID
Order by @MaxID desc

SQL Server 2005查询帮助

4 个答案: