为什么我的“左连接”会抛出“意外令牌:开启”错误?

时间:2012-08-07 16:37:01

标签: sql hibernate ejb

我有两个要运行的查询:

2012-08-07 11:24:02,561 ERROR [org.hibernate.hql.PARSER] (http-0.0.0.0-8080-12) line 1:105: unexpected token: ON
2012-08-07 11:24:02,686 ERROR [org.jboss.aspects.tx.TxPolicy] (http-0.0.0.0-8080-12) javax.ejb.EJBTransactionRolledbackException: org.hibernate.hql.ast.QuerySyntaxException: unexpected token: ON near line 1, column 105 
[SELECT count(o) from ejb.entity.News o LEFT JOIN NewsNewsDistributionServiceLink p ON o.id = p.newsId WHERE o.statusId = ?1 AND p.newsDistServiceCode is ?2]

2012-08-07 11:26:15,605 ERROR [org.hibernate.hql.PARSER] (http-0.0.0.0-8080-12) line 1:105: unexpected token: ON
2012-08-07 11:26:15,609 ERROR [org.jboss.aspects.tx.TxPolicy] (http-0.0.0.0-8080-12) javax.ejb.EJBTransactionRolledbackException: org.hibernate.hql.ast.QuerySyntaxException: unexpected token: ON near line 1, column 105 
[SELECT count(o) from entity.News o LEFT JOIN NewsNewsDistributionServiceLink p ON o.id = p.newsId WHERE o.companyId = ?1 AND o.statusId = ?2 AND p.newsDistServiceCode is ?3]

我在SQuirreL SQL客户端中运行了以下命令:

select * from news n left join news_news_distribution_service_link nl
on n.id=nl.news_id
where news_distribution_service_code is null

这将返回结果,但是当我为我的java servlet翻译它时,它会抛出该错误。

新闻表:

id -PK
company_id
user_id
title
type_id
status_id
location
is_immediate
contents
created_date
last_modified_date
release_date
delete_date
corrected_news_id
can_distribute
was_distributed

NewsNewsDistLink表:

id -PK 
news_id - this is equal to the id in News
news_distribution_service_code

代码:

String _query = "SELECT COUNT(o) FROM News o " + (filter.tierGroup != null ? TIER_GROUP_JOIN : "") + "WHERE ";
            WhereClauseBuilder builder = getWhereClause(filter);
            _query+= builder.where.toString();

            Query query = em.createQuery(_query);
            query.setHint("org.hibernate.cacheable", true);
            builder.bind(query);

whereClauseBuilder()基本上在“where”之后添加了params,bind()基本上将参数与?#及其值绑定在一起。最后,p.newsDistServiceCode在大多数情况下很可能为空(> 95%)。

1 个答案:

答案 0 :(得分:0)

因为查询不是SQL查询,而是HQL查询。 SQL和HQL是两种不同的语言。 SQL适用于表和列,而HQL适用于Hibernate实体和关联。

请参阅Hibernate documentation