我有一些课程:
class Window(object):
def __init__(self, name):
self.wind_name = name
def getWindowName(self):
return 'wnd' + self.wind_name
class Control(object):
def __init__(self, name, wnd):
self.contrl_name = name
setattr(self, 'getWindowName', wnd.getWindowName)
setattr(self, 'wind_name', wnd.wind_name)
def getControlName(self):
return (self.getWindowName(), 'unk' + self.contrl_name)
class Button(Control):
def __init__(self, name, wnd):
super(Button, self).__init__(name, wnd)
def getControlName(self):
return (self.getWindowName(), 'btn' + self.contrl_name)
wnd = Window('MyApp')
btnOK = Button('OK', wnd)
btnOK.getControlName() # work ok., return ('wndMyApp', 'btnOK')
btnOK.wind_name = 'NewApp'
btnOK.getControlName() # does not work properly., return ('wndMyApp', 'btnOK')
如何从类Control
的对象扩展类Button
| Window
以访问对象{{中的函数getWindowName
和字段wind_name
1}}?
是否可以在类控件中创建字段btnOK
,或在self.wnd = wnd
中添加方法setWindowName
?
我无法从班级Window
继承班级Control
!这不符合逻辑。
答案 0 :(得分:2)
Python允许从多个类继承,即
class Button(Control, Window):
...
但在这种情况下,你应该确切地知道你在做什么(谈到Pythons Method Resolution Order(MRO))。我建议你阅读这本小书:Python Attributes and Methods。
答案 1 :(得分:0)
您可以使用属性属性
class Window(object):
def __init__(self, name):
self.wind_name = name
def getWindowName(self):
return 'wnd' + self.wind_name
class Control(object):
def __init__(self, name, wnd):
self.contrl_name = name
self.wnd = wnd
setattr(self, 'getWindowName', wnd.getWindowName)
def get_wind_name(self):
return self.wnd.wind_name
def set_wind_name(self, v):
self.wnd.wind_name = v
wind_name = property(get_wind_name, set_wind_name)
def getControlName(self):
return (self.getWindowName(), 'unk' + self.contrl_name)
class Button(Control):
def __init__(self, name, wnd):
super(Button, self).__init__(name, wnd)
def getControlName(self):
return (self.getWindowName(), 'btn' + self.contrl_name)
wnd = Window('MyApp')
btnOK = Button('OK', wnd)
print btnOK.getControlName() # work ok., return ('wndMyApp', 'btnOK')
btnOK.wind_name = 'NewApp'
print btnOK.getControlName()