Question

我有两个MySQL表，一个用于水果，一个用于蔬菜，我想查询这些表的内容，并在一个大的JSON字典中返回两组结果，用Fruits键控返回水果数组和Vegetables返回蔬菜阵列。它目前不起作用（返回null）。

这是我目前的代码：

//query each table for every object
$fruitResult = mysql_query("SELECT * FROM Fruits");
$vegResult = mysql_query("SELECT * FROM Vegetables");

//set up an array for each kind of object
$fruits = array();
$vegetables = array();

while ($fruitRow = mysql_fetch_assoc($fruitResult)) {
    //add each result from Fruit table to array
    $fruits[] = $fruitRow;
}
while ($vegRow = mysql_fetch_assoc($vegResult)) {
    //add each result from Veggie table to array
    $vegetables[] = $vegRow;
}

//create dictionary
$dictionary = array("Fruit"=>$fruits,"Vegetables"=>$vegetables);

echo json_encode($dictionary);

我可以将这些事情分开，只是

echo json_encode($fruits);
echo json_encode($vegetables);

然后返回两个单独的数组。任何人都可以放任何光吗？我希望我的回答看起来像这样：

[{"Fruit":
    [{"id":"0","name":"apple","color":"red"},
    {"id":"1","name":"strawberry","color":"red"},
    {"id":"2","name":"grape","color":"purple"}],
{"Vegetables":
    [{"id":"0","name":"pea","color":"green"},
    {"id":"1","name":"asparagus","color":"green"},
    {"id":"2","name":"corn","color":"yellow"}]
}]

来自PHP-MySQL查询的键控JSON字典响应

0 个答案: