Question

我有一张像......的桌子。

    | id | name             | meetingID | meeting_type | status | recurring_time | attendee_passwd | moderator_passwd | date_created        | timezone  | meeting_datetime    | reminder | duration | created_by_id | sms_no | conferenceID | meeting_logout_url | max_participants | participants_id |
    +----+------------------+-----------+--------------+--------+----------------+-----------------+------------------+---------------------+-----------+---------------------+----------+----------+---------------+--------+--------------+--------------------+------------------+-----------------+
|  7 | 6august          | REG_524   |              |   NULL |                | 90200           | 18614            | 0000-00-00 00:00:00 | GMT  5.45 | 2012-08-06 03:00:00 |        0 | 60       |             1 |  12356 |         NULL | http://log.com     |               20 |            NULL |

我正在尝试按当前日期过滤表格，因此我使用以下查询

 SELECT *  from demo_meeting WHERE created_by_id IN(SELECT id FROM demo_user WHERE user_name = ' Sang') and meeting_datetime=curdate();

但我得到空集而不是得到结果。

请告诉我我在这里做错了什么

Answer 1

您正在将日期时间与日期进行比较。

尝试将日期时间转换为日期，如下所示：

SELECT *  from demo_meeting WHERE created_by_id IN ( SELECT id FROM demo_user WHERE user_name = ' Sang') AND DATE(meeting_datetime) = curdate();

Answer 2

SELECT *  from demo_meeting WHERE created_by_id IN(SELECT id FROM demo_user WHERE user_name = ' Sang') and DATE_FORMAT(meeting_datetime, '%Y-%m-%d')=curdate();

Answer 3

尝试使用DATE( )功能设置日期格式。顺便说一下，加入表格比SubQuery 更高效

SELECT  a.*
FROM    demo_meeting a 
            INNER JOIN demo_user b
                ON a.created_by_id = b.ID
WHERE   b.user_name = 'Sang' AND
        DATE(a.meeting_datetime) = DATE(curdate())

Answer 4

您正在将curdate（）与字段meeting_datetime进行比较，该字段具有数据类型datetime / timestamp;你真正需要做的是比较日期（meeting_datetime）和curdate（）。

查询将是： SELECT * from demo_meeting WHERE created_by_id IN（SELECT id FROM demo_user WHERE user_name =＆＃39; Sang＆＃39;）和date(meeting_datetime)=curdate();

希望它会帮助你。

Mysql按当前日期过滤数据

4 个答案: