我有几个（MySQL）表。有趣的是CampaignRegion存储Campaign的外键和City，County，District，{{1}的外键}或State。始终只有一个特定于位置的外键设置，其他是Country。
NULL表如下所示：
CampaignRegion我现在需要一个查询来选择mysql> describe CampaignRegion;
+-------------+---------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------------+---------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| campaign_id | int(11) | YES | MUL | NULL | |
| country_id | int(11) | YES | MUL | NULL | |
| state_id | int(11) | YES | MUL | NULL | |
| district_id | int(11) | YES | MUL | NULL | |
| county_id | int(11) | YES | MUL | NULL | |
| city_id | int(11) | YES | MUL | NULL | |
+-------------+---------+------+-----+---------+----------------+
。我有Campaign，需要获得与City本身或Campaigns或City或County匹配的District或State的{{1}}。
这实际上非常简单，我想出了类似的东西：
Country但是，我希望得到City的结果集，其排序首先匹配SELECT count(id) as campaign_count, campaign_id
FROM CampaignRegion
WHERE (city_id = 32076 OR district_id = 127 OR state_id = 7 OR country_id = 156)
GROUP BY campaign_id
HAVING campaign_count > 0;
，然后匹配Campaigns，然后匹配City的结果集等等（就像查询中County的顺序一样。有没有一种简单的方法可以做到这一点？我会根据District（第一次匹配）OR做什么？这个查询位于SELECT或Campaign？你怎么看？
感谢您的帮助。
答案 0 :(得分：1)
我认为这就是你要找的东西：
SELECT count(id) as campaign_count, campaign_id
FROM CampaignRegion
WHERE (city_id = 32076 OR district_id = 127 OR state_id = 7 OR country_id = 156)
GROUP BY campaign_id
HAVING campaign_count > 0;
ORDER BY (city_id = 32076) DESC, (country_id = 156) DESC, (state_id = 7) DESC, (district_id = 127) DESC;