初学者的python套接字

Question

我知道python，我正试图进入更复杂的东西。我发现这个代码，它应该工作。我收到了客户端第14行的错误，mrecv的返回     ValueError：int（）的基数为10的无效文字; ''

我将两个文件分开并调用服务器，然后调用客户端。当我运行它们时服务器就说了     闭幕 客户说     recieved-＆GT;再见！ 没有任何反应，但是当我向客户端输入你好时，我得到了上面显示的错误。我可能/可能做错了，这是我第一次使用套接字或服务器做任何事情。如果你知道我做错了什么，请帮助，如果你有任何其他好的网站或教程，我会很感激。这是所有代码（不是我的）

python套接字聊天示例， 作者：Ankur Shrivastava， 许可证：GPL v3

服务器

import socket
import threading
import time

SIZE = 4

soc = socket.socket(socket.AF_INET,socket.SOCK_STREAM)
soc.bind(('127.0.0.1',5432))
soc.listen(5)

class CThread(threading.Thread):
    def __init__(self,c):
        threading.Thread.__init__(self)
        self.conn = c
        self.stopIt=False

    def mrecv(self):
        data = self.conn.recv(SIZE)
        self.conn.send('OK')
        msg = self.conn.recv(int(data))
        return msg

    def run(self):
        while not self.stopIt:
            msg = self.mrecv()
            print 'recieved->  ',msg

def setConn(con1,con2):
    dict={}
    state = con1.recv(9)
    con2.recv(9)
    if state =='WILL RECV':
        dict['send'] = con1 # server will send data to reciever
        dict['recv'] = con2
    else:
        dict['recv'] = con1 # server will recieve data from sender
        dict['send'] = con2
    return dict

def msend(conn,msg):
    if len(msg)<=999 and len(msg)>0:
        conn.send(str(len(msg)))
        if conn.recv(2) == 'OK':
            conn.send(msg)
    else:
        conn.send(str(999))
        if conn.recv(2) == 'OK':
            conn.send(msg[:999])
            msend(conn,msg[1000:]) # calling recursive


(c1,a1) = soc.accept()
(c2,a2) = soc.accept()
dict = setConn(c1,c2)
thr = CThread(dict['recv'])
thr.start()
try:
    while 1:
        msend(dict['send'],raw_input())
except:
    print 'closing'
thr.stopIt=True
msend(dict['send'],'bye!!!')# for stoping the thread
thr.conn.close()
soc.close()

的客户端

import socket
import threading
SIZE =4
class client(threading.Thread):
    def __init__(self,c):
        threading.Thread.__init__(self)
        self.conn = c
        self.stopIt = False

    def mrecv(self):
        data = self.conn.recv(SIZE)
        self.conn.send('OK')
        return self.conn.recv(int(data))

    def run(self):
        while not self.stopIt:
            msg = self.mrecv()
            print 'recieved-> ',msg

soc1 = socket.socket(socket.AF_INET,socket.SOCK_STREAM)
soc1.connect(('127.0.0.1',5432))
soc1.send('WILL SEND') # telling server we will send data from here

soc2 = socket.socket(socket.AF_INET,socket.SOCK_STREAM)
soc2.connect(('127.0.0.1',5432))
soc2.send('WILL RECV') # telling server we will recieve data from here

def msend(conn,msg):
    if len(msg)<=999 and len(msg)>0:
        conn.send(str(len(msg)))
        if conn.recv(2) == 'OK':
            conn.send(msg)
    else:
        conn.send(str(999))
        if conn.recv(2) == 'OK':
            conn.send(msg[:999])
            msend(conn,msg[1000:]) # calling recursive
thr = client(soc2)
thr.start()
try:
    while 1:
        msend(soc1,raw_input())
except:
    print 'closing'
thr.stopIt=True
msend(soc1,'bye!!') # for stoping the thread
thr.conn.close()
soc1.close()
soc2.close()

我尝试输入一个数字，它给了我同样的错误。当我从线上取出int并运行客户端时，它说它必须是一个数字......还有其他想法吗？

Answer 1

接收器需要4个字节的字符串数据来表示要接收的剩余数据的长度。在这种情况下，前四个字节不包含有效的文本整数（如“1234”），因此对int()的调用失败。