Question

我的表中有一个包含各种条目的varchar字段。如何使用order by语句获得以下结果：

1
2
3
4
5
6
7
8
9
10
Steinstrass 1
Steinstrass 2
Steinstrass 3
Steinstrass 4
Steinstrass 5
Steinstrass 6
Steinstrass 7
Steinstrass 8
Steinstrass 9
Steinstrass 10

Answer 1

这对我有用：

mysql> select * from sorting;
+---------+
| field1  |
+---------+
| 1       |
| 4       |
| 10      |
| Item 1  |
| Item 10 |
| Item 0  |
| 0       |
+---------+
7 rows in set (0.00 sec)

mysql> select field1 from sorting order by length(field1),field1 asc;
+---------+
| field1  |
+---------+
| 0       |
| 1       |
| 4       |
| 10      |
| Item 0  |
| Item 1  |
| Item 10 |
+---------+
7 rows in set (0.00 sec)

Answer 2

试试这个：

order by (case when left(str, 1) between '0' and '9' then 1
               else 0
          end) desc,
         (case when left(str, 1) between '0' and '9' then cast(str as unsigned)
          end),
         cast(substring(str, instr(' ', str)+1, 100) as unsigned)

这适用于任意初始字符串。它假设在初始字符串和数字之间有一个空格。

按字母和数字排序首先从数字开始，然后是“数字字符串”

2 个答案: