package michael.week.pkg5;
class Employee {
String Fname ;
String Lname;
String PhoneNum;
String Address;
void setFirst(String First){
Fname = First ;
}
void setlast(String Last){
Lname = Last ;
}
void setAddress (String address){
Address = address ;
}
void setPhone (String Phone){
PhoneNum = Phone ;
}
void display (){
System.out.println ("the Fist name is :"+ Fname + " , the last name is : " + Lname + " ,the address is : "+ Address+ " ,the phone is : "+ PhoneNum);
}
}
package michael.week.pkg5;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class MichaelWeek5 {
/**
* @param args the command line arguments
*/
public static void main(String[] args) throws IOException {
class Stck {
Employee stck [] = new Employee[10];
int x ;
void stck (){
x= -1 ;
}
Employee push (Employee item){
if (x == 9){
System.out.println ("Stack is full");
}else stck[++x] = item ;
return stck[x];
}
Employee pop (){
if (x <0){
System.out.println (" Stack underflow");
return stck [x];
}else
return stck[x++];
}
}
InputStreamReader inp = new InputStreamReader(System.in);
BufferedReader br = new BufferedReader(inp);
String info2 = null ;
Stck obj = new Stck();
Employee obj2 = new Employee ();
int w = -1 ;
for (int r=1 ;r>0; ){
System.out.println("please enter add to add new employee");
System.out.println("please enter pop to pop the last added employee");
System.out.println("please enter exit to exit");
String choice = br.readLine();
if(choice.equals("add")){
System.out.println(w);
if (w >= 9){
System.out.println("you reached the maxmum number !");
continue ;
}
else {
w++;
obj.stck ();
String info ;
System.out.println ("please enter Employee first name :");
info = br.readLine();
System.out.println ("please enter Employee last name name :");
info = br.readLine();
System.out.println ("please enter Employee address :");
info = br.readLine();
System.out.println ("please enter Employee phone number :");
info = br.readLine();
}
} else if(choice.equals("pop")){
obj.pop();
w--;
}else if(choice.equals("exit"))
break ;
else {System.out.println (choice + " is wrong choice !") ;
}
}
}
}
问候， 我是java新手，我正在研究这个程序.......我需要知道如何将数据推送到stck？ 注意：push的参数是employee类型，Employee包含First，Last，Phone和address。我怎么能推动他们每个人？ 这就是我所做的，我的导师拒绝了
package week.pkg5;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class Week5 {
/**
* @param args the command line arguments
*/
public static void main(String[] args) throws IOException {
class Employee {
String [] Fname = new String [10];
String[] Lname= new String [10];
String[] PhoneNum= new String [10];
String[] Address = new String [10];
int x= -1 ;
void increment(){
x++;
}
void PushFirst(String First){
Fname[x] = First ;
}
void Pushlast(String Last){
Lname [x] = Last ;
}
void PushPhone (String Phone){
PhoneNum [x] = Phone ;
System.out.println ("the Fist name is :"+ Fname [x]+ " , the last name is : " + Lname [x] + " ,the address is : "+ Address[x] + " ,the phone is : "+ PhoneNum[x]);
}
void PushAddress (String address){
Address [x] = address ;
}
void pop (){
if (x < 0){
System.out.println (" No Empolyee !");
}
else {
System.out.println ("the Fist name is :"+ Fname [x]+ " , the last name is : " + Lname [x] + " ,the address is : "+ Address[x] + " ,the phone is : "+ PhoneNum[x]);
x--;
}
}
void display (){
if (x < 0){
System.out.println (" No Empolyee !");
}
else {
for (int q = 0 ; q <=x ; q++){
System.out.println ((q+1)+"- "+"the First name is :"+ Fname [q]+ " , the last name is : " + Lname [q] + " ,the address is : "+ Address[q] + " ,the phone is : "+ PhoneNum[q]);
}
}
}
}
InputStreamReader inp = new InputStreamReader(System.in);
BufferedReader br = new BufferedReader(inp);
Employee obj = new Employee();
int w = -1 ;
for (int r=1 ;r>0; ){
System.out.println("please enter add to add new employee");
System.out.println("please enter display to display all employees list");
System.out.println("please enter pop to pop the last added employee");
System.out.println("please enter exit to exit");
String choice = br.readLine();
if(choice.equals("add")){
System.out.println(w);
if (w >= 9){
System.out.println("you reached the maxmum number !");
continue ;
}
else {
w++;
obj.increment();
String info ;
System.out.println ("please enter Employee first name :");
info = br.readLine();
obj.PushFirst(info);
System.out.println ("please enter Employee last name name :");
info = br.readLine();
obj.Pushlast(info);
System.out.println ("please enter Employee address :");
info = br.readLine();
obj.PushAddress(info);
System.out.println ("please enter Employee phone number :");
info = br.readLine();
obj.PushPhone(info);}
} else if(choice.equals("display")){
obj.display();
} else if(choice.equals("pop")){
obj.pop();
w--;
}else if(choice.equals("exit"))
break ;
else {System.out.println (choice + " is wrong choice !") ;
}
}
}
}
答案 0 :(得分：0)
您需要创建一堆员工，然后将整个员工对象推送到堆栈。
import java.util.Stack;
...
Employee emp = new Employee();
Stack<Employee> stack = new Stack<Employee>();
stack.push(emp);
答案 1 :(得分：0)
创建一个类的对象后说（这里是stck），它将通过调用下面显示的方法来保存数据
class std
{
int id;
string name;
public:
void set_id(int i)
{
id=i;
}
void set_name(string n)
{
name = n;
}
void disp()
{
system.out.println("name"+name+" and id = "+id);
}
};
main()
{
std s = new std();
s.set_id(1);
s.set_name("sunmoon");
s.disp();
}
所以在这里你可以观察到s被认为是堆栈，我们推送一个人的细节，就像你可以创建一个对象数组并推送n个人的细节。
答案 2 :(得分：0)
您对建模数据的方式有几个问题。
问题＃1（最大的问题）： 员工不应该拥有堆栈的任何内部表示。想想现实世界中的物体。在您的示例中，每个Employee都应该具有：
所以成员字段：
String [] Fname = new String [10];
String[] Lname= new String [10];
String[] PhoneNum= new String [10];
String[] Address = new String [10];
int x= -1 ;
不属于。这导致我们......
问题＃2 ：您对堆栈建模的方式只允许固定数量的条目 - 在您的情况下为10。这不是堆栈应该如何工作。如果你不确定，请阅读Stack是什么。您可以使用LinkedList在Java中建模堆栈 - 或者使用Java提供的内置Stack。如果您决定创建自己的版本，则需要创建的重要操作是：
我的建议是首先对员工和实践进行建模，然后从JDK中推出并将其从内置堆栈中弹出，直到您在尝试创建自己的操作之前真正了解操作。