Oracle SQL查询:如何使用count

时间:2012-08-03 19:51:53

标签: sql oracle

我有以下格式的数据

userid  amount  term  APR
1        10       5    1
1        10       4    2
2        20       6    1
2        20       4    3
2        20       3    1

我想按金额,期限,APR做订单,所以在输出中我想要最大金额和相应的期限,APR。如果金额相同,请选择一个最大期限,如果期限也相同则相同。但这三者的结合总是独一无二的。

输出栏:

userid,  amount, term, apr, numberOfRowsForEachUser
  1       10       5   1      2
  2       20       6   1      3

问题:我可以获得前四列,但不知道如何获得“总计不提供优惠”或“每位用户的总行数”。

我的查询看起来像这样。

select 
  userid,amount,term,apr
  from 
( select userid, amount, term,  apr
   RANK() OVER (PARTITION BY userid ORDER BY amount,term,apr) amount_rank,   
from 
   tableXYZ
) 
where amount_rank = 1 

2 个答案:

答案 0 :(得分:5)

只需添加COUNT(*)分析函数

即可
select 
  userid,amount,term,apr, cnt
  from 
( select userid, amount, term,  apr
   RANK() OVER (PARTITION BY userid ORDER BY amount,term,apr) amount_rank,   
   COUNT(*) OVER (PARTITION BY userid) cnt
from 
   tableXYZ
) 
where amount_rank = 1 

答案 1 :(得分:2)

我喜欢Justing的回答(+1),但仍想提供一个更直观的替代答案:

select x.userid,x.amount,x.term,x.apr,y.cnt
from tableXYZ x, (select userid, COUNT(1) cnt from tableXYZ group by userid) y
where x.term = (select max(term) from tableXYZ xx where xx.userid = x.userid)
and x.userid = y.userid

你可以玩它here