XPath - 在两个DIV之间选择文本(),通过匹配文本来识别

时间:2012-08-03 19:21:26

标签: html css xpath scrapy

我有这个HTML,

<div id="General" class="detailOn">
    <div class="tabconstraint"></div>
    <div id="InstitutionMain" class="detailseparate">
        <div id="InstitutionMain_divINFORight" style="float:right;width:40%"></div>
        <div style="font-weight:bold;padding-top:6px">Special Learning Opportunities</div>
        Distance learning opportunities<br>

        <div style="font-weight:bold;padding-top:6px">Student Services</div>
        Remedial services<br>
        Academic/career counseling service<br>

        <div style="font-weight:bold;padding-top:6px">Credit Accepted</div>
        Dual credit<br>
        Credit for life experiences<br>
    </div>
</div>

我想提取

text() = between [Div/text() = "Special Learning Opportunities</div>
        Distance learning opportunities"] and [div/text()="Student Services"] 

类似于其他div

我尝试了这段代码,它为我提供了所识别的div后面的所有文字,

div[1]/div[contains(text(),"Special Learning Opportunities")]/following-sibling::text()

虽然这段代码给了我div之前的所有文字

div[1]/div[contains(text(),"Student Services")]/preceding-sibling::text()

有没有办法准确获取指定DIV之间的所有文本。 提前致谢。

我正在使用python 2.x和scrapy进行抓取。

注意:我目前的方法: - 使用这三个xpath

item['SLO']=site.select('div[1]/div[contains(text(),"Special Learning Opportunities")]/following-sibling::text()').extract()
item['SS']=site.select('div[1]/div[contains(text(),"Student Services")]/following-sibling::text()').extract()
item['CA']=site.select('div[1]/div[contains(text(),"Credit Accepted")]/following-sibling::text()').extract()

我得到三个这样的项目,

item['SLO']=['Distance learning opportunities','Remedial services',' Academic/career counseling service','Dual credit','Credit for life experiences']
item['SS']=['Remedial services',' Academic/career counseling service','Dual credit','Credit for life experiences']
item['CA']=['Dual credit','Credit for life experiences']

然后我在python列表上工作以获得我想要的东西,

但我认为在XPath中应该有更快的方法来实现这一目标。

3 个答案:

答案 0 :(得分:4)

您可以将“a和b之间的文本”直接翻译为XPath,作为“text()[previous-sibling = a and next-sibling = b]”

即:

//text()[(preceding-sibling::div[1]/text() = "Special Learning Opportunities") and (following-sibling::div[1]/text() = "Student Services")]

应该有效。

(虽然我测试它时失败了,但它似乎是我的XPath解释器中的一个错误)

答案 1 :(得分:2)

你走了,不像以前的回答那么优雅,但嘿 - 至少它有效! : - )

div[1]//div[contains(text(),"Special Learning Opportunities")]/following-sibling::node()[position() <= count( div[1]//div[contains(text(),"Student Services")]/following-sibling::node()) + 1]

答案 2 :(得分:1)

你可以试试这个..

//div[contains(text(),"Special Learning Opportunities")]//following-sibling::text()[./following-sibling::div[contains(text(),'Student Services')]]