我是Kintetic.js的新手,我正在尝试做网格。宽度为800px,高度为400px。我想要方块(20x20)来覆盖那个区域。每个方格都有1px边框。所以像这样:
var box = new Kinetic.Rect({
width: 20,
height: 20,
fill: 'transparent',
stroke: 'rgba(0, 0, 0, 0.02)'
});
为了填充画布,我有一个糟糕的for循环:
for (var i = 0; i <= this.field.getWidth(); i = i + 20) {
for (var i2 = 0; i2 <= this.field.getHeight(); i2 = i2 + 20) {
var cbox = box.clone({x: i, y: i2});
this.grid.add(cbox);
}
}
this.grid 是一个Kinetic.Layer。这段代码的第一个问题是它非常慢,在网格显示之前我得到了500ms的延迟。但最糟糕的是,如果我在cbox上放置一个mouseover和mouseout事件来改变填充颜色,那真的很慢。我就是这样做的:
cbox.on('mouseover', function () {
this.setFill('black');
self.grid.draw();
});
cbox.on('mouseout', function () {
this.setFill('transparent');
self.grid.draw();
});
所以我的问题是如何改善这个代码和性能?
答案 0 :(得分:5)
如何使用直线制作网格并使用一个矩形进行光标突出显示? 在这里我为你写了这个例子: http://jsfiddle.net/e_aksenov/R72Xu/30/
var CELL_SIZE = 35,
w = 4,
h = 5,
W = w * CELL_SIZE,
H = h * CELL_SIZE;
var make_grid = function(layer) {
var back = new Kinetic.Rect({
x: 0,
y: 0,
width: W,
height: H,
fill: "yellow"
});
layer.add(back);
for (i = 0; i < w + 1; i++) {
var I = i * CELL_SIZE;
var l = new Kinetic.Line({
stroke: "black",
points: [I, 0, I, H]
});
layer.add(l);
}
for (j = 0; j < h + 1; j++) {
var J = j * CELL_SIZE;
var l2 = new Kinetic.Line({
stroke: "black",
points: [0, J, W, J]
});
layer.add(l2);
}
return back; //to attach mouseover listener
};
var cursor_bind = function(layer, grid_rect, rect) {
grid_rect.on('mouseover', function(e) {
var rx = Math.floor(e.x / CELL_SIZE);
var ry = Math.floor(e.y / CELL_SIZE);
rect.setPosition(rx * CELL_SIZE, ry * CELL_SIZE);
layer.draw();
});
};
var stage = new Kinetic.Stage({
container: "kinetic",
width: 800,
height: 600,
draggable: true
});
var layer = new Kinetic.Layer();
var rect = new Kinetic.Rect({
x: 0,
y: 0,
width: CELL_SIZE,
height: CELL_SIZE,
fill: "#00D2FF",
stroke: "black",
strokeWidth: 4
});
var gr = make_grid(layer);
cursor_bind(layer, gr, rect);
// add the shape to the layer
layer.add(rect);
// add the layer to the stage
stage.add(layer);