Question

我是MDX世界的新手..

我想基于3行对列进行分组。但是，还需要加入第4排...... 我的疑问是：

SELECT 
 (    { 
   [Measures].[Live Item Count] 
          } 
 ) DIMENSION PROPERTIES parent_unique_name ON COLUMNS, 


 Crossjoin(
 crossjoin(

  [Item].[Class].&[Light],
  [Item].[Style].&[Fav]
  [Item].[Season Year].members),
  [Item].[Count].children )    on rows
FROM Cube

输出如下：

Light(Row) | FAV(Row) | ALL(Row)  | 16(Row) | 2(col)
Light(Row) | FAV(Row) | ALL(Row)  | 7(Row)  | 1(col)
Light(Row) | FAV(Row) | 2012(Row) | 16(Row)| 2(col)
Light(Row) | FAV(Row) | 2011(Row) | 7(Row) | 1(col)

但是，我希望我的输出显示为：

Light(Row) | FAV(Row) | ALL(Row)  |        | 3(col)
Light(Row) | FAV(Row) | 2012(Row) | 16(Row)| 2(col)
Light(Row) | FAV(Row) | 2011(Row) | 7(Row) | 1(col)

即，我想将前两行分组，以便第3列中没有重复的'ALL'。

提前致谢

Answer 1

尝试这一点 - 使用级别名称Season Year，使用属性名称Season Year将获取每个成员，而不是所有成员：

SELECT 
 (    { 
   [Measures].[Live Item Count] 
          } 
 ) DIMENSION PROPERTIES parent_unique_name ON COLUMNS, 


 Crossjoin(
 crossjoin(

  [Item].[Class].&[Light],
  [Item].[Style].&[Fav]
  [Item].[Season Year].[Season Year].members),
  [Item].[Count].children )    on rows
FROM Cube

Answer 2

如果[Item].[Count]层次结构中有所有成员，则可以使用此查询：

SELECT {[Measures].[Live Item Count]} DIMENSION PROPERTIES parent_unique_name ON COLUMNS, 
Crossjoin(
  Crossjoin([Item].[Class].&[Light], [Item].[Style].&[Fav]),
  Union(
    Crossjoin({"All member of [Item].[Season Year]"}, {"All member of [Item].[Count]"}),
    Crossjoin(Except([Item].[Season Year].members, {"All member of [Item].[Season Year]"}), [Item].[Count].children),
  ) ON ROWS
FROM Cube

在MDX查询中分组

2 个答案: