我想在google地图上通过上一页的lat长度渲染路线(由html表格发送) 并将接收值放在php隐藏类型上,然后通过jquery拉取值并定义一个开始,结束点 从隐藏类型的值最后调用route函数但它没有显示路径
我尝试在渲染部分设置警报它工作正常但不显示路线。我不知道为什么
这是我的代码
<?php
//get lat long from previous page html form
$press = $_POST["send"];
$lat1 = $_POST["lat1"];
$long1 = $_POST["long1"];
$lat2 = $_POST["lat2"];
$long2 = $_POST["long2"];
?>
<!DOCTYPE html>
<head>
<script type="text/javascript" src="./jquery.min.js"></script>
<script type="text/javascript" src="http://maps.googleapis.com/maps/api/js?key=my_key&sensor=false"></script>
<script type="text/javascript">
var directionsDisplay;
var directionsService = new google.maps.DirectionsService();
var map;
var rendererOptions = {draggable: true}; //define dragble direction
function initialize() {
directionsDisplay = new google.maps.DirectionsRenderer(rendererOptions);
var center = new google.maps.LatLng(13.76493,100.5383);
var mapOptions = {
zoom:7,
mapTypeId: google.maps.MapTypeId.ROADMAP,
center: center
}
map = new google.maps.Map(document.getElementById("map_canvas"), mapOptions); //render map
calcRoute(); //call route function
}
function calcRoute()
{//get lat long from hidden type
$(document).ready(function(){
var lat1 = $("#lat1").val();
var long1 = $("#long1").val();
var lat2 = $("#lat2").val();
var long2 = $("#long2").val();
var start = new google.maps.LatLng(lat1,long1);//define start point
var end = new google.maps.LatLng(lat2,long2);//define end point
var request = {
origin:start,
destination:end,
travelMode: google.maps.DirectionsTravelMode.DRIVING
};
directionsService.route(request, function(result, status) {
if (status == google.maps.DirectionsStatus.OK) {
directionsDisplay.setDirections(result);
alert("DO"); //it's show alert when redirect from previous page
}
});
});
}
</script>
</head>
<body onload="initialize()">
<div id="map_canvas" style="width:500px; height:400px"></div>
<?php
//put value from previous page on hidden type
echo "<input type='hidden' id='lat1' value='$lat1'>";
echo "<input type='hidden' id='long1' value='$long1'>";
echo "<input type='hidden' id='lat2' value='$lat2'>";
echo "<input type='hidden' id='long2' value='$long2'>";
?>