Question

我将JSON文件解析为字典，并且在另一步骤中我想为couchDB构建一个post请求。

解析工作正常，但如果我发布我得到一个错误。我认为它与post字符串中的转义序列有关。

这是代码：

NSString *filePath = [[NSBundle mainBundle] pathForResource:@"data" ofType:@"json"];

NSString *fileContent = [[NSString alloc] initWithContentsOfFile:filePath]; 

SBJsonParser *parser = [[SBJsonParser alloc] init];

NSDictionary *data = (NSDictionary *) [parser objectWithString:fileContent error:nil]; 



// getting the data from file
NSString *_id = (NSString *) [data objectForKey:@"_id"];
NSString *rev_ =  self.rev;
NSString *_herausgeber = (NSString *) [data objectForKey:@"Herausgeber"];
NSString *_nummer = (NSString *) [data objectForKey:@"Nummer"];
NSNumber *_deckung = [data objectForKey:@"Deckung"];
NSString *_waerhung = (NSString *) [data valueForKey:@"Waehrung"];

NSDictionary *_inhaber = (NSDictionary *) [data objectForKey:@"Inhaber"]; 
NSString *_name = (NSString *) [_inhaber objectForKey:@"Name"];
NSString *_vorname = (NSString *) [_inhaber objectForKey:@"Vorname"];
NSNumber *_maennlich = (NSNumber *) [_inhaber objectForKey:@"maennlich"];

NSArray *_hobbys = (NSArray *) [_inhaber objectForKey:@"Hobbys"];
    NSString *_hobby0 = [_hobbys objectAtIndex:0];
    NSString *_hobby1 = [_hobbys objectAtIndex:1];
    NSString *_hobby2 = [_hobbys objectAtIndex:2];
NSNumber *_alter = (NSNumber *) [_inhaber objectForKey:@"Alter"];

NSArray * _kinder = (NSArray *) [_inhaber objectForKey:@"Kinder"];
    NSString *_kind0 = [_kinder objectAtIndex:0];
    NSString *_kind1 = [_kinder objectAtIndex:1];
    NSString *_kind2 = [_kinder objectAtIndex:2];
NSString *_partner = (NSString *) [_inhaber objectForKey:@"Partner"];

   [parser release];

//post string:

NSString *post = [NSString stringWithFormat:@"{\"_id\":\"%@\",\"_rev\":\"%@\",\"Herausgeber\":\"%@\",\"Nummer\":\"%@\",\"Deckung\":%@,\"Waehrung\":\"%@\",\"Inhaber\":{\"Name\":\"%@\",\"Vorname\":\"%@\",\"maennlich\":%@,\"Hobbys\":[\"%@\",\"%@\",\"%@\"],\"Alter\":%@,\"Kinder\":[\"%@\",\"%@\",\"%@\"],\"Partner\":%@}}",_id,rev_,_herausgeber,_nummer,_deckung,_waerhung,_name,_vorname,_maennlich,_hobby0,_hobby1,_hobby2,_alter,_kind0,_kind1,_kind2,_partner];


//post header:

NSData *postData = [post dataUsingEncoding:NSUTF8StringEncoding allowLossyConversion:YES];
NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]];

NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
[request setURL:[NSURL URLWithString:cdbURL]];
[request setHTTPMethod:@"PUT"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:postData];

我得到的错误：

回复：{“error”：“bad_request”，“reason”：“无效的UTF-8 JSON：＆LT;＆LT; \ “{\\” _ ID \\ “：\\” 161eba7093799b610502bdfba5004281 \\”，\\ “_转\\”：\\ “199-bb065cbd0a365b188fc492cc22453d74 \\”，\\ “Herausgeber \\”：\ \ “SAP \\”，\\ “Nummer \\”：\\ “1234-5678-9012-3456 \\”，\\ “Deckung \\”：2000000，以\\ “Waehrung \\”：\\”丽珠\\ “\\ ”INHABER \\“：{\\ ”名称\\“：\\ ”Mustermann \\“，\\ ”Vorname \\“：\\ ”最大\\“，\\” maennlich \\ “：1，\\” Hobbys \\ “：[\\” Reiten \\”，\\ “Golfen \\”，\\ “Lesen \\”]，\\ “ALTER \\”：42， \\ “金德\\”：[\\ “最大\\”，\\ “莫里茨\\”，\\ “莉莎\\”]，\\ “伙伴\\”：}} \“＆GT;＆GT; “}

我该如何解决这个问题？

Answer 1

就个人而言，我会避免自己构建JSON后期字符串，而是使用SBJson的[NSObject JSONRepresentation]函数。

然后你可以填写NSDictionary并让API为你构建JSON。

NSString *_id = @"161";
NSString *_rev = @"199";
NSString *_herausgeber = @"SAP";

NSMutableDictionary *toPost = [NSMutableDictionary dictionary];
[toPost setObject:_id forKey:@"_id"];
[toPost setObject:_rev forKey:@"_rev"];
[toPost setObject:_herausgeber forKey:@"Herausgeber"];

NSLog(@"JSON: %@", [toPost JSONRepresentation]);

给出：

JSON: {"_id":"161","_rev":"199","Herausgeber":"SAP"}

将JSON文件解析为POST请求目标C.

1 个答案: