Question

我正在尝试为用户提供在时间刻度上搜索的选项。我想要一个下拉菜单，在下拉菜单中显示选项，如下所示：

搜索自：3天前，1周前，1个月前，6个月前，1年。等。

我知道我必须使用DateTime.now.to_date - 3.days所以rails知道我想在3天前查询，但我不确定如何让用户将3天前的选项视为文本在下拉列表中，但查询DateTime.now.to_date - 3.days

由于

我的搜索视图目前看起来像这样：

    <h1>Search</h1>

<% if @project_search.total_entries > 0 %>
<%= form_tag search_path, method: :get do %>

Client :
<%= select(@projects, :client, Project.all.map {|p| [p.client]}.uniq, :prompt => "-Any-", :selected => params[:client]) %></br>

Industry :
<%= select(@projects, :industry, Project.all.map {|p| [p.industry]}.uniq, :prompt => "-Any-", :selected => params[:industry]) %></br>

Role :
<%= select(@projects, :role, Project.all.map {|p| [p.role]}.uniq, :prompt => "-Any-", :selected => params[:role]) %></br>

Technologies :
<%= select(@projects, :tech, Project.all.map {|p| [p.tech]}.uniq, :prompt => "-Any-", :selected => params[:tech]) %></br>

Business Division :

<%= select(@projects, :business_div, Project.all.map {|p| [p.business_div]}.uniq, :prompt => "-Any-", :selected => params[:business_div]) %></br>

Project Owner :
<%= select(@projects, :project_owner, Project.all.map {|p| [p.project_owner]}.uniq, :prompt => "-Any-", :selected => params[:project_owner]) %></br>

Exception PM
<%= select(@projects, :exception_pm, Project.all.map {|p| [p.exception_pm]}.uniq, :prompt => "-Any-", :selected => params[:exception_pm]) %></br>




<%= select_tag "start_date", options_for_select({
      "3 days ago"   => 3.days,   # =    259_200 sec.
      "1 week ago"   => 1.week,   # =    604_800 sec.
      "1 month ago"  => 1.month,  # =  2_592_000 sec.
      "6 months ago" => 6.months, # = 15_552_000 sec.
      "1 year ago"   => 1.year,   # = 31_557_600 sec.
    }) %>


Project Dates between

<%#=  text_field_tag("start_date") %>

and

<%= text_field_tag("end_date") %></br>


Status :

<%= select(@projects, :status, Project.all.map {|p| [p.status]}.uniq, :prompt => "-Any-", :selected => params[:status]) %></br>

Keywords :

<%= text_field_tag :keywords, params[:keywords] %></br>

<%= submit_tag "Search", name: nil %>

<% end %>

我的模特：

class Project < ActiveRecord::Base
  attr_accessible :business_div, :client, :customer_benifits, :edited_date, :end_date, :entry_date, :exception_pm, :financials, :industry, :keywords, :lessons_learned, :project_name, :project_owner, :role, :start_date, :status, :summary, :tech

validates_presence_of :business_div, :client, :customer_benifits, :end_date, :exception_pm, :financials, :industry, :keywords, :lessons_learned, :project_name, :project_owner, :role, :start_date, :status, :summary, :tech


def self.search(search_client, search_industry, search_role, search_tech, search_business_div, search_project_owner, search_exception_pm, search_status, search_start_date, search_end_date, search_keywords) 
  return scoped unless search_client.present? || search_industry.present? || search_role.present? || search_tech.present? || search_business_div.present? || search_project_owner.present? || search_exception_pm.present? || search_status.present? || search_start_date.present? || search_end_date.present? || search_keywords.present?




  where(['client LIKE ? AND industry LIKE ? AND role LIKE ? AND tech LIKE ? AND business_div LIKE ? AND project_owner LIKE ? AND exception_pm LIKE ? AND status LIKE ? AND DATE(start_date) BETWEEN ? AND ? AND DATE(end_date) BETWEEN ? AND ? AND keywords LIKE ?', 
      "%#{search_client}%", "%#{search_industry}%" , "%#{search_role}%" , "%#{search_tech}%" , "%#{search_business_div}%" , 
      "%#{search_project_owner}%" , "%#{search_exception_pm}%" , "%#{search_status}%", 
      search_start_date, search_end_date, search_start_date, search_end_date,"%#{search_keywords}%"
    ])



end


def self.paginated_for_index(projects_per_page, current_page)
    paginate(:per_page => projects_per_page, :page => current_page)
  end

end

Answer 1

您可以以秒为单位指定时间范围：

<%= select_tag "ago", options_for_select({
      "3 days ago"   => 3.days,   # =    259_200 sec.
      "1 week ago"   => 1.week,   # =    604_800 sec.
      "1 month ago"  => 1.month,  # =  2_592_000 sec.
      "6 months ago" => 6.months, # = 15_552_000 sec.
      "1 year ago"   => 1.year,   # = 31_557_600 sec.
    }) %>

在查询中使用该值：

Model.where("created_at >", Time.now - params[:ago])

Answer 2

使用由github人写的chronic gem支持的自然语言处理。从用户获得人类可读格式的范围＆amp;然后使用chronic将它们解析为ruby理解的完全有效日期，并且可以作为参数传递给Active Record以查询数据库

这里有一些例子：

1.9.3p194 :001 > require 'chronic'
 => true 
1.9.3p194 :002 > Chronic.parse '3 days ago'
 => 2012-07-31 15:20:59 +0530 
1.9.3p194 :003 > Chronic.parse '1 week ago'
 => 2012-07-27 15:22:15 +0530 
1.9.3p194 :004 > Chronic.parse '1 month ago'
 => 2012-07-03 15:22:26 +0530 
1.9.3p194 :005 > Chronic.parse '6 months ago'
 => 2012-02-03 15:23:25 +0530 
1.9.3p194 :006 > Chronic.parse '1 year ago'
 => 2011-08-03 15:23:34 +0530

现在，你也可以在这里获得一些优点，也可以做一些像

这样的事情

1.9.3p194 :007 > Chronic.parse 'last night'
 => 2012-08-02 22:00:00 +0530

README中提供了更多示例，但由于其非常灵活，我会说您在接受用户输入时也可以获得创意。因此，您可以允许用户选择任意日期，而不是选择框中的预定值（您仍可以执行此操作）。我知道这不是传统方式，但我认为使用NLP非常酷！所以try it

Ruby on Rails：选择日/月/年前搜索

2 个答案: