Question

IM有一个像这样的JSON字符串

 [{"group_id":"1","group_name":"coupler system","subgroups":[{"group_id":"9","group_name":"core","subgroups":0},{"group_id":"10","group_name":"dual","subgroups":0}]},{"group_id":"2","group_name":"powersource\/engine","subgroups":[{"group_id":"11","group_name":"petrol","subgroups":[{"group_id":"13","group_name":"ECO-whisper","subgroups":[{"group_id":"15","group_name":"yes","subgroups":0},{"group_id":"16","group_name":"no","subgroups":0}]}]},{"group_id":"12","group_name":"electric","subgroups":[{"group_id":"14","group_name":"mains","subgroups":[{"group_id":"17","group_name":"220V","subgroups":0},{"group_id":"18","group_name":"110V","subgroups":0}]}]}]},{"group_id":"3","group_name":"tool connections","subgroups":[{"group_id":"19","group_name":"1(STO)","subgroups":0},{"group_id":"20","group_name":"2(MTO)","subgroups":0}]},{"group_id":"4","group_name":"oil content","subgroups":[{"group_id":"21","group_name":"2L?","subgroups":0},{"group_id":"22","group_name":"4L?","subgroups":0},{"group_id":"23","group_name":"6L?","subgroups":0}]},{"group_id":"5","group_name":"hose reels","subgroups":[{"group_id":"24","group_name":"no","subgroups":0},{"group_id":"25","group_name":"yes","subgroups":0}]},{"group_id":"6","group_name":"tool support + carry","subgroups":[{"group_id":"29","group_name":"no","subgroups":0},{"group_id":"30","group_name":"yes","subgroups":[{"group_id":"31","group_name":"wheelset","subgroups":[{"group_id":"32","group_name":"yes","subgroups":0},{"group_id":"33","group_name":"no","subgroups":0}]}]}]},{"group_id":"7","group_name":"weight","subgroups":[{"group_id":"34","group_name":"<=15?","subgroups":0},{"group_id":"35","group_name":"<=25?","subgroups":0},{"group_id":"36","group_name":"<=50?","subgroups":0},{"group_id":"37","group_name":"<=100?","subgroups":0}]},{"group_id":"8","group_name":"dimensions","subgroups":[{"group_id":"38","group_name":"SR10","subgroups":0},{"group_id":"39","group_name":"SR20","subgroups":0},{"group_id":"40","group_name":"SR31\/32","subgroups":0},{"group_id":"41","group_name":"SR40","subgroups":0},{"group_id":"42","group_name":"SR41\/42","subgroups":0}]}]

我需要使用Jquery将此JSON设置为有效的HTML表结构，如下所示，我该如何实现它 enter image description here

这就是我到目前为止所尝试过的......我用递归循环部分

  <script type="text/javascript">
        $(document).ready(function(){
           var jsondata = jQuery.parseJSON($.trim($('#groupdata').html())); //the above JSON

           var str = '';
           str +='<table>';
           str +='<tr>';




             for(j=0;j<jsondata.length;j++){



                 str +='<td>'+jsondata[j]['group_name']+'</td>';
        // here i want to call the same loop again if it has subgroups


             }
             str +=' </tr>';
             str+='</table>';
             $('#container').html(str);
        });
    </script>

Answer 1

你可以先摆脱for循环并使用Jquery .each（）函数。为了让你开始尝试这样的事情。 v =当前节点的值，k =当前密钥

$jQuery.each(jsondata, function(k, v) { create(k, v, 0) });

function create(k, v, n) { 
  //print your table the way you want it

  //if the value is an object, loop through each instance of the subcategories
  if(v instanceof Object) {
    $.each(v, function(key, val, n) {
      create(key, val, n+1)
    });
  }
  return;
}

您需要填写空白以使行/列按您希望的方式制作，但这是一个模板，用于执行递归调用来解析Object。如果你需要这样一个变量，n var用于检查递归的深度，我认为你可能会尝试做什么。 n = 0是顶部，n = 1将是一个级别，n = 2将是两个级别等等...

Answer 2

这有三个部分：

如何进行递归
如何构建HTML
如何使用jQuery

当你有这样的东西时，你需要（a）简化（b）将其分解成各个部分。使用更简单的数据来计算递归并构建一些HTML。当它工作时，引入您的实际数据的子集，使其工作，等等。

粗略的模板。我会用这个json：

var json = '[{ "first": "1", "second": "2", "sub": 0 },{ "first": "3", "second": "4", "sub": [{ "first": "3.1", "second": "3.2", "sub": 0 }] }]';

要进行递归，你必须将“行构建器”分解为一个单独的函数，以便在需要时自行调用。

如下所示。您将不得不使用它来处理您自己的数据，将html调整为您想要的等等。您需要做的第一件事就是理解它。

我不会假装这是完美的，并且可能会有性能改进，但这应该让你朝着正确的方向前进...快乐解析......

$(document).ready(function () {
    var data = $.parseJSON(json);
    var html = "<table>";
    var rows = recurse(data);
    html += rows + "</table>";
    document.write(html);
});

function recurse(data) {
    var row = "";
    for (var e in data) { //each object at this level
        row += "<tr>";
        row += "<td>" + data[e].first + "</td>";
        row += "<td>" + data[e].second + "</td>";
        row += "<td>";
        if (data[e].sub.length == 1) {
            var sub = "<table>";
            sub += recurse(data[e].sub)
            sub += "</table>";
            row += sub;
        }
        row += "</td></tr>";
    }
    return row;
}

Answer 3

Recursion需要功能。所以，建立一个：

function generateTableMarkup(data) {
    for (var i=0; i<data.length; i++) {
        // do something
        if (data[i].subgroups) {
            generateTableMarkup(data[i].subgroups);
        }
    }
}
generateTableMarkup(JSON.parse(...));

JSON与Jquery的递归循环问题

3 个答案: