嘿试图从一个Controller(模板)到另一个(Field)获取id。试图让模板的id自动出现在表单的add(view)输入字段中。
FieldsController包含我们尝试过的细分:
$template = $this->Template->find('first');
$current_template = $this->Template->request->data($template['Template']['id']);
添加字段视图中的输入字段:
echo $this->Form->input('templates_id', array('label'=>'Template ID: ', 'type' => 'text', 'default' => $current_template['templates_id']));
那么我们可以做些什么来完成这项任务呢?我认为我尝试过的东西会起作用,但是不会出现“在非对象上调用成员函数find()”。
'templates_id'是'Field'表中的外键,它链接到'Template'表中的'id'。
编辑:
添加LoadModel(下面)并吐出错误:调用非对象上的成员函数data()。
我们正确地执行以下操作吗?或者应该是$ this-> request-> data($ template ['Template'] ['id']);
$this->loadModel('Template');
$template = $this->Template->find('first');
$current_template = $this->Template->request->data($template['Template']['id']);
编辑2:
FieldsController with add function:
function add(){
$this->set('title_for_layout', 'Please Enter Your Invoice Headings');
$this->set('stylesheet_used', 'style');
$this->set('image_used', 'eBOXLogo.jpg');
$this->Session->setFlash("Please create your required fields.");
$this->loadModel('Template');
$template = $this->Template->find('first');
//$current_template = $template['Template']['id'];
// right way to do it, but Template is undefined, and says undefined var
//$current_template = $this->request->data['Template']['id'];
// makes sense with the find, no errors, but still doesnt print in form, says undefined var
$current_template = $this->request->data($template['Template']['id']);
if($this->request->is('post'))
{
$this->Field->create();
if ($this->Field->save($this->request->data))
{
if($this->request->data['submit'] == "type_1")
{
$this->Session->setFlash('The field has been saved');
$this->redirect( array('controller' => 'fields','action' => 'add'));
}
if($this->request->data['submit'] == "type_2")
{
$this->Session->setFlash('The template has been saved');
$this->redirect( array('controller' => 'templates','action' => 'index'));
}
}
else
{
$this->Session->setFlash('The field could not be saved. Please, try again.');
}
}
}
名为add:
的视图中的表单<?php
echo $this->Form->create('Field', array('action'=>'add'));
echo $this->Form->create('Field', array('action'=>'add'));
echo $this->Form->input('name', array('label'=>'Name: '));
echo $this->Form->input('description', array('label'=>'Description: '));
echo $this->Form->input('templates_id', array('label'=>'Template ID: ', 'type' => 'text', 'default' => $current_template['templates_id']));//this would be the conventional fk fieldname
echo $this->Form->button('Continue adding fields', array('name' => 'submit', 'value' => 'type_1'));
echo $this->Form->button('Finish adding fields', array('name' => 'submit', 'value' => 'type_2'));
echo $this->Form->end();
?>
答案 0 :(得分:1)
$this->Template->request->data($template['Template']['id']);
错了。
看看MVC模式:
调度员将数据发送到控制器。
现在看看你的代码:
$this->Template->request->data($template['Template']['id']);
$this
是控制器。
->Template
调用相关模型。
request->data()
使用View中的数据从此模型调用函数。
简而言之:您将视图中的数据传递给模型,从而打破了MVC模式。
应该是:
$this->request->data['Template']['id'];
编辑: 我认为有两个问题:
我认为应该是:
$ current_template = $ this-&gt; request-&gt; data ['Field'] ['template_id'];
$current_template = $this->request->data($template['Template']['id']);
未设置此变量。
这样的东西:
$this->set(compact('current_template'));
答案 1 :(得分:0)
要从其他模型获取数据,您必须先加载它:
$this->loadModel('Template');
$this->Template->find('first');