Question

我们正在使用zend_db_table，因为Zend Framework抱怨两个事务处于活动状态，我们遇到了一些问题：

[message:protected] => There is already an active transaction
[string:Exception:private] => 
[code:protected] => 0
[file:protected] => /var/www/vhosts/test.local/private/library/Zend/Db/Adapter/Pdo/Abstract.php
[line:protected] => 305
[trace:Exception:private] => Array

这是Controller中的代码：

     public function convertAction()
{
    $this->setNoRender();

    // If the quote is a copy of a previous one, fetch all the datas
    $quoteId = Zend_Filter::filterStatic($this->getRequest()->getParam('qte_id'), 'int');
    $quoteTable = new Model_QuotesTable();
    $quoteRow = $quoteTable->findById($quoteId);
    if (count($quoteRow)) {
        $clonedId = $quoteRow->convertToJob();
        $this->flashMessageRedirect('Quotation successfully converted', '/jobs/edit/job_id/' . $clonedId);
    } else {
        $this->flashMessageRedirect('Unable to find the quote to be converted', '/quotes');
    }
}

在QuotesTableRow中调用此函数，它扩展了zend_db_table_abstract：

    public function convertToJob()
{
    $db = $this->_getTable()->getAdapter();
    $db->beginTransaction();

    $jobsTable = new Model_JobsTable();

    try {

        /*
         * Update the status of the old row to match the $status passed into this function
         */
        $this->qte_status = "Accepted";
        $this->save();

        /*
         * Create new row with the same details as above
         */

        $newRow = $jobsTable->createRow();

        $newRow->job_title = $this->qte_title;
        $newRow->job_cus_id = $this->qte_cus_id;
        $newRow->job_enq_id = $this->qte_enq_id;
        $newRow->job_qte_id = $this->qte_id;
        $newRow->job_title = $this->qte_title;
        $newRow->job_description = $this->qte_description;
        $newRow->job_work_location_id = $this->qte_work_location_id;
        $newRow->job_work_category_id = $this->qte_work_category_id;
        $newRow->job_work_type_id = $this->qte_work_type_id;
        $newRow->job_cus_code = $this->qte_cus_code;
        $newRow->job_cus_name = $this->qte_cus_name;
        $newRow->job_wt_ref_code = $this->qte_wt_ref_code;
        $newRow->job_wt_description = $this->qte_wt_description;
        $newRow->job_wl_code = $this->qte_wl_code;
        $newRow->job_wl_description = $this->qte_wl_description;
        $newRow->job_wc_ref_code = $this->qte_wc_ref_code;
        $newRow->job_wc_description = $this->qte_wc_description;
        $newRow->job_qte_title = $this->qte_title;
        $newRow->job_datetime_created = date('Y-m-d H:i:s');

        $newRowId = $newRow->save();

        $db->commit();
        return $newRowId;
    } 
    catch (Exception $e) { 
        $db->rollback(); 

        echo('<pre>');
        print_r($e);
        echo('</pre>');
        exit();

        throw new Exception($e->getMessage());
        return false;
    }
}

另外，它似乎与我们不在的模型有关，因为如果我们用与模型相关的mod（）函数注释该行，脚本正在工作，而当我们发表评论时它返回相同的错误另一个保存（）。

Answer 1

这个错误是从MySQL返回的，而ZF只是告诉你错误信息。

您是否在同一个请求中启动了两个交易？这可以解释为什么你收到此错误消息，或者你可能在事务中间有一个中止的连接而且它没有被回滚或自动提交。

每个数据库连接只应启动一个事务。如果您需要两个模型在单个请求中拥有活动事务，那么您需要获得2个单独的数据库连接。

请参阅Bill Karwin关于此问题的this (great) answer。

您可以运行查询SHOW ENGINE InnoDB STATUS;以获取活动交易列表。如果您有一个已打开并且您没有来自PHP / ZF的活动事务，那么请尝试关闭该事务，否则您将不得不查看您的代码并查看在同一请求中如何启动两个事务。

Answer 2

感谢您的回答，我们找到了解决方案。问题是，我们两次使用save()函数;使用save()更改第一个insert()，解决了问题：

public function convertToJob()
{

    $db = $this->_getTable()->getAdapter();
    $db->beginTransaction();

    $jobsTable = new Model_JobsTable();

    try {

        /*
         * Create new row with the same details as above
         */

        $data = array(
            'job_cus_id'            =>  $this->qte_cus_id,
            'job_enq_id'            =>  $this->qte_enq_id,
            'job_qte_id'            =>  $this->qte_id,
            'job_title'             =>  $this->qte_title,
            'job_description'       =>  $this->qte_description,
            'job_work_location_id'  =>  $this->qte_work_location_id,
            'job_work_category_id'  =>  $this->qte_work_category_id,
            'job_work_type_id'      =>  $this->qte_work_type_id,
            'job_cus_code'          =>  $this->qte_cus_code,
            'job_cus_name'          =>  $this->qte_cus_name,
            'job_wt_ref_code'       =>  $this->qte_wt_ref_code,
            'job_wt_description'    =>  $this->qte_wt_description,
            'job_wl_code'           =>  $this->qte_wl_code,
            'job_wl_description'    =>  $this->qte_wl_description,
            'job_wc_ref_code'       =>  $this->qte_wc_ref_code,
            'job_wc_description'    =>  $this->qte_wc_description,
            'job_qte_title'         =>  $this->qte_title,
            'job_datetime_created'  =>  date('Y-m-d H:i:s')
        );

        $newRowId = $jobsTable->insert($data);

        /*
         * Update the status of the old row to match the $status passed into this function
         */

        $this->qte_status = "Accepted";
        $this->save();

        $db->commit();

        return $newRowId;
    } 
    catch (Exception $e) {
        throw new Exception($e->getMessage());
        return false;
    }
}

Zend框架抱怨“已经有一个活跃的交易”

2 个答案: