我想在没有应用html的情况下访问单选按钮(性别字段)中的jsongrid值。我尝试了简单的javascript函数,它在UI中工作正常,但是值来自html输入,但我希望值来自jsongrid.Plz帮助我..
这是JavaScript代码
<script type="text/javascript">
$j.ajax({
url:"UserGender",
type: "GET",
data: datasourses,
dataType: "json",
success: function (data){
$.each(data, function(i, selectedItem) {
alert("paramValue: " + selectedItem.paramValue + ", paramCode: " +
data.selectedItem.paramCode);
});
}
});
</script>
这是html
<input type="radio" name="Female" >
<input type="radio" name="Male" >
Json代码
{
"jsonWrapperforGrid": {
"page": "1",
"total": "2",
"rows": [
{
"tenantId": 0,
"paramType": "UserGender",
"paramCode": "F",
"langCode": "en",
"paramValue": "Female"
},
{
"tenantId": 0,
"paramType": "UserGender",
"paramCode": "M",
"langCode": "en",
"paramValue": "Male",
"paramBlob": ""
}
]
}
}
提前致谢
答案 0 :(得分:4)
$.each(data.jsonWrapperforGrid.rows, function() {
alert("paramValue: " + this.paramValue + ", paramCode: " + this.paramCode);
});