为什么会这样:
static TreeMap<String, int[]> configs = new TreeMap<String, int[]>();
int[] upperarms_body = {2,3,4,6};
int[] left_arm = {1,2};
int[] right_arm = {6,7};
int[] right_side = {5,6,7};
int[] head_sternum = {3,4};
configs.put("upperarms_body", upperarms_body);
configs.put("left_arm", left_arm);
configs.put("right_arm", right_arm);
configs.put("right_side", right_side);
configs.put("head_sternum", head_sternum);
// create a config counter
String[] combi = new String[configs.keySet().size()];
Set<String> s = configs.keySet();
int g = 0;
for(Object str : s){
combi[g] = (String) str;
}
而这不是:
static TreeMap<String, int[]> configs = new TreeMap<String, int[]>();
int[] upperarms_body = {2,3,4,6};
int[] left_arm = {1,2};
int[] right_arm = {6,7};
int[] right_side = {5,6,7};
int[] head_sternum = {3,4};
configs.put("upperarms_body", upperarms_body);
configs.put("left_arm", left_arm);
configs.put("right_arm", right_arm);
configs.put("right_side", right_side);
configs.put("head_sternum", head_sternum);
//get an array of thekeys which are strings
String[] combi = (String[]) configs.keySet().toArray();
答案 0 :(得分:8)
方法toArray()
会返回Object[]
实例,无法转换为String[]
,就像Object
实例< / em>无法转换为String
:
// Doesn't work:
String[] strings = (String[]) new Object[0];
// Doesn't work either:
String string = (String) new Object();
但是,因为您可以将String
分配给Object
,您还可以将String
放入Object[]
(这可能会让您感到困惑):
// This works:
Object[] array = new Object[1];
array[0] = "abc";
// ... just like this works, too:
Object o = "abc";
反过来不会起作用,当然
String[] array = new String[1];
// Doesn't work:
array[0] = new Object();
当你这样做时(来自你的代码):
Set<String> s = configs.keySet();
int g = 0;
for(Object str : s) {
combi[g] = (String) str;
}
您实际上并未向Object
投射String
实例,而是投放了String
个实例,声明为Object
类型到String
。
您的问题的解决方案是以下任何一种:
String[] combi = configs.keySet().toArray(new String[0]);
String[] combi = configs.keySet().toArray(new String[configs.size()]);
的更多信息,请参阅Javadoc
答案 1 :(得分:3)
Object[]
可以添加任何类型的对象。 String[]
只能包含字符串或null
如果你能按照你建议的方式进行投射,你就能做到。
Object[] objects = new Object[1];
String[] strings = (String[]) objects; // won't compile.
objects[0] = new Thread(); // put an object in the array.
strings[0] is a Thread, or a String?