Question

在ajax响应中返回多个错误证明是麻烦的，如果回显多个错误，1＆amp; 2例如变为12.在数组中返回响应数据的最佳方法是什么？非常感谢任何帮助，提前谢谢。

这是将表单POST到PHP验证器

的功能

$("document").ready(function() {
    $("#btn-signup").click(function() {
        var first_name = $("#fname_up").val();
        var last_name = $("#lname_up").val();
        var vemail = $("#email_up").val();
        var password = $("#password_up").val();
        var cpassword = $("#cpassword_up").val();
        var dataString = 'firstname='+first_name+'&lastname='+last_name+'&email='+vemail+'&password='+password+'&cpassword='+cpassword;
        $.ajax({
            type: "POST",
            url: "-signup.php",
            data: dataString,
            success: function(response){
                if (response == 1) {
                    console.log("1");
                }
                if (response == 2) {
                    console.log("2");
                }
                if (response == 3) {
                    console.log("3");
                }
                if (response == 4) {
                    console.log("4");
                }
                if (response == 5) {
                    console.log("5");
                }
                if (response == 6) {
                    console.log("6");
                }
                if (response == 7) {
                    console.log("7");
                }
                if (response == 12) {
                    console.log("You got to here");
                }
            }
        });
    return false;
    });
});

这是PHP表单验证器。

<?php

session_start();
require_once "database.php";
db_connect();

$errors = array();

// If request is a form submission
if($_SERVER['REQUEST_METHOD'] == 'POST'){
  // Validation

  // Check first_name is non-blank
  if(0 === preg_match("/\S+/", $_POST['firstname'])){
    echo "1";
  }

  // Check last_name is non-blank
  if(0 === preg_match("/\S+/", $_POST['lastname'])){
    echo "2";
  }

  // Check email is valid (enough)
  if(0 === preg_match("/.+@.+\..+/", $_POST['email'])){
    echo "3";
  }

  // Check password is valid
  if(0 === preg_match("/.{6,}/", $_POST['password'])){
    echo "4";
  }

  // Check password confirmation_matches
  if(0 !== strcmp($_POST['password'], $_POST['cpassword'])){
    echo "5";
  }

  // If no validation errors
  if(0 === count($errors)){

    // Sanitize first, last, and email
    $firstname = mysql_real_escape_string($_POST['firstname']);
    $lastname  = mysql_real_escape_string($_POST['lastname']);
    $email      = mysql_real_escape_string($_POST['email']);
    $password      = mysql_real_escape_string($_POST['password']);
    $cpassword     = mysql_real_escape_string($_POST['cpassword']);

    // Generate pseudo-random salt
    $salt = sha1(microtime() . $_POST['password']);

    // Generate password from salt
    $password = sha1($salt . $_POST['password']);


    // Insert user into the database
    $query = "INSERT INTO.......

    $result = mysql_query($query);

    if(mysql_errno() === 0){
      // Registration successful
      $user_id = mysql_insert_id();
      log_in($user_id);
      echo "9";
    } else if (preg_match("/^Duplicate.*email.*/// get rid of the two lines beforei", mysql_error())){
      echo "10";
    }  
  }
}

Answer 1

你得到的错误是什么？您的AJAX网址是否已正确分配？

我认为你应该给出“-signup.php”文件的绝对路径。像/path/to/signup-file.php

这样的东西

为什么你使用 if（0 === count（$ errors））而不是 if（count（$ errors）== 0），同样适用于以上验证。您可以使用 if（空（$ errors））。

如需更多帮助，请将错误写给我们

注册表单失败PHP AJAX

1 个答案: