Question

我试图截断从我的数据库中检索到的书名，以便在条形码标签上打印。我不能从查询中截断它，因为我需要整个标题出现在同一页面上的表中。这就是我所拥有的：

   $.ajax({
        type: "POST",
        url: "advanceProcess.php",
        dataType: "json",
        data: ({sourceID: $('#sourceID').val(), fromDate: $('#fromDate').val(), toDate: $('#toDate').val()}),
        success: function(data){
            if(data.isbn == null ){
                $("#acctRecords").append('<tr><td>No Records Found</td></tr>');
            }else{
                //append general data
                for(var x=0;x<data.isbn.length;x++)
                {
                    $("#acctRecords").append('<tr><td id="tableSKU">'+data.tempsku[x]+
                    '</td><td id="tableISBN">'+data.isbn[x]+
                    '</td><td id="tableTitle">'+data.title[x]+
                    '</td><td id="tableOrderid">'+data.orderId[x]+
                    '</td><td id="tableQtyBought">'+data.quantity[x]+
                    '</td><td id="tableCost">'+data.cost[x]+
                    '</td><td id="tabledateCreated">'+data.dateCreated[x]+
                    '</td><td id="tableWeight">'+data.weight[x]+
                    '</td><td id="tableCheckNumber">'+data.checkNumber[x]+'</td></tr>');
                }// end of for loop
                //refreshes the tablesorter plugin
                $("#acctRecords").trigger("update");
    //Print the bar codes
    sku = data.tempsku;
    title = data.title[x];
    //console.log(JSON.stringify(data));
    title = title.substr(0,16);
    var x=0;
    for (x=0;x<title.length;x++)
    {   
        first += '$("#'+indexGlobal+'").barcode("'+sku[x]+'", "codabar",{barHeight:40, fontSize:30, output:"bmp"});';
        second += '<div class="wrapper"><img src="../images/temp.jpg" /><div id="'+indexGlobal+
        '"></div><div class="fullSKU">&nbsp &nbsp &nbsp '+sku[x]+'</div><br/><div class="title">'+title[x]+
        '</div></div><br/><div class="page-break"></div>';
        indexGlobal++;
    }

一切都很好，除了标题太长。目前我收到一个错误，指出：TypeError：title.substr不是一个函数。我在这里和谷歌做了一些研究，似乎我的代码是正确的。有什么想法吗？

编辑：以下是JSON的结果：

"title":["Understanding and Applying Medical Anthropology","The Ethical Chemist : Professionalism and Ethics in Science","Magic, Witchcraft, and Religion: A Reader in the Anthropology of Religion","Principles of Cancer Biology","AIDS and Accusation: Haiti and the Geography of Blame","In Search of Respect: Selling Crack in El Barrio (Structural Analysis in the Social Sciences)"]

编辑2：我更新了脚本以显示整个ajax调用以及返回结果的方式。

Answer 1

您正在使用多个标题，以便从阵列中获取第一个：

title = data.title[0];
title = title.substr(0,16);

如果您想为每个标题构建条形码：

for(x=0; x<data.title.length; x++)
{
   title = data.title[x];
   title = title.substr(0,16);

   // Build barcode

}

Answer 2

//Your object [JSON]
var obj = {"title":["Understanding and Applying Medical Anthropology","The Ethical     Chemist : Professionalism and Ethics in Science","Magic, Witchcraft, and Religion: A Reader in the Anthropology of Religion","Principles of Cancer Biology","AIDS and Accusation: Haiti and the Geography of Blame","In Search of Respect: Selling Crack in El Barrio (Structural Analysis in the Social Sciences)"]}

//Result
obj.title[0] // Understanding and Applying Medical Anthropology

用jquery和substring截断书名

2 个答案: