我有一个返回数据结构的查询:
Course Math Science Computer Chemistry
------ ---- ------- -------- ---------
CI101 98
CI101 87
CI101 78
CI101 102
CI101 23
CI101 56
CI101 89
CI101 45
如何使用SQL在以下结构中:
Course Math Science Computer Chemistry
------ ---- ------- -------- ---------
CI101 98 78 23 45
CI101 87 102 56
CI101 89
这是我试过的SQL:
select course,
case
when subject = 'MATH' then
count
end as MATH,
case
when subject = 'SCIENCE' then
count
end as SCIENCE,
case
when subject = 'COMPUTER' then
count
end as COMPUTER,
case
when subject = 'CHEMISTRY' then
count
end as CHEMISTRY
from t_course
GROUP BY course, subject, count
表格结构:
Course Subject Count
------ ------- -----
CI101 Math 98
....
非常感谢。
答案 0 :(得分:1)
试试这个:
由于我没有Oracle而我没有看到这个问题的任何答案,我在sql server中完成了这个。这可以很容易地转换为Oracle sql。
我认为,唯一要求转换的部分是 ROW_NUMBER()over(按[count]排序)为row_num ,这基本上是为每个集合提供序列号
select CO.course,MA.count as 'MATH',SC.count as 'SCIENCE',CO.count as 'COMPUTER',CH.count as 'CHEMISTRY' from
(select course,[count],ROW_NUMBER() over(order by [count]) as row_num from t_course where subject = 'MATH')MA full outer join
(select course,[count],ROW_NUMBER() over(order by [count]) as row_num from t_course where subject = 'SCIENCE')SC on SC.row_num=MA.row_num full outer join
(select course,[count],ROW_NUMBER() over(order by [count]) as row_num from t_course where subject = 'COMPUTER')CO on CO.row_num=SC.row_num full outer join
(select course,[count],ROW_NUMBER() over(order by [count]) as row_num from t_course where subject = 'CHEMISTRY')CH on CO.row_num=CH.row_num
请参阅SQL小提琴演示here