Question

我需要解析一个Skype日志，抓住所有通话时长并添加它们，并找出整个聊天记录的总呼叫持续时间。

样品：

[3/12/2012 11:36:44 AM] *通话结束，持续时间21:33 *

我认为我需要将preg_match与正确的正则表达式一起使用。如果可以在更好的同时将实际时间戳存储在数组中。

我认为我真正难以理解的是实际的正则表达式规则，只需要获取呼叫持续时间。

Answer 1

试试这个

(?i)\[(?P<time_stamp>[^[]+)\]\s*[*]\s*[a-z ,]+(?P<duration>(?:\d{2}:?){2,3})\s*[*]

<强>解释

"
(?i)               # Match the remainder of the regex with the options: case insensitive (i)
\[                 # Match the character “[” literally
(?P<time_stamp>    # Match the regular expression below and capture its match into backreference with name “time_stamp”
   [^[]               # Match any character that is NOT a “[”
      +                  # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
)
\]                 # Match the character “]” literally
\s                 # Match a single character that is a “whitespace character” (spaces, tabs, and line breaks)
   *                  # Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
[*]                # Match the character “*”
\s                 # Match a single character that is a “whitespace character” (spaces, tabs, and line breaks)
   *                  # Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
[a-z ,]            # Match a single character present in the list below
                      # A character in the range between “a” and “z”
                      # One of the characters “ ,”
   +                  # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
(?P<duration>      # Match the regular expression below and capture its match into backreference with name “duration”
   (?:                # Match the regular expression below
      \d                 # Match a single digit 0..9
         {2}                # Exactly 2 times
      :                  # Match the character “:” literally
         ?                  # Between zero and one times, as many times as possible, giving back as needed (greedy)
   ){2,3}             # Between 2 and 3 times, as many times as possible, giving back as needed (greedy)
)
\s                 # Match a single character that is a “whitespace character” (spaces, tabs, and line breaks)
   *                  # Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
[*]                # Match the character “*”
"

Answer 2

您可以使用：

 \*.+?([0-9]+:){1,2}([0-9]+)

然后它可以捕获第一个*之后的HH：MM：SS和MM：SS。

解析Skype日志

2 个答案: