如何使用叙述者播放所有单词?

时间:2012-08-01 02:31:18

标签: c# winforms soundplayer

我的项目是文本到语音项目,这是我的代码,

string amma = myacess.Text;
// string[] words = Regex.Split(amma,"*");
char[] delimeter = new char[] { '*' };
string[] words = amma.Split(delimeter, StringSplitOptions.RemoveEmptyEntries);
for( int i = 0; i < words.Length; i++ ) {
    string audio = words[i];
    if( audio == "a" ) {
        SoundPlayer sndplayr = new SoundPlayer( WindowsFormsApplication1.Properties.Resources.aa );
        sndplayr.Play();

    }
    if( audio == "u" ) {
        SoundPlayer sndplayr = new SoundPlayer( WindowsFormsApplication1.Properties.Resources.i );
        sndplayr.Play();
    }
}

但是输入文字“au”它只会播放“u”声。但我放了断点并按F11然后只播放声音和声音。背后的原因是什么?你能帮助我吗?

2 个答案:

答案 0 :(得分:0)

  

但我放了断点并按F11然后它只播放声音而你   声音。背后的原因是什么?你能帮助我吗?

我认为问题在于for循环太快了。

所以你可以用这种方式使用Timer(System.Windows.Forms.Timer):

private Timer timer;
private int i;

string amma = myacess.Text;
// string[] words = Regex.Split(amma,"*");
char[] delimeter = new char[] { '*' };
string[] words = amma.Split(delimeter, StringSplitOptions.RemoveEmptyEntries);

//...

timer = new Timer();
timer.Interval = 100; //milliseconds 
timer.Tick = += new EventHandler(timer_Tick);
timer.Enabled = true; //start the timer

i = 0;

void timer_Tick(object sender, EventArgs e){
    if(i < word.Lenght){
       string audio = words[i];
       if( audio == "a" ) {
           SoundPlayer sndplayr = new SoundPlayer( WindowsFormsApplication1.Properties.Resources.aa );
           sndplayr.Play();   
       }
       if( audio == "u" ) {
           SoundPlayer sndplayr = new SoundPlayer( WindowsFormsApplication1.Properties.Resources.i );
           sndplayr.Play();
       }

       i++; //increase i to change letter like in the loop
    }
    else{
       timer.Enabled = false; //stop the timer
       i = 0;
    }
}

答案 1 :(得分:0)

使用SoundPlayer.PlaySync Method代替SoundPlayer.Play。通过这个,您可以在上一个声音结束后开始下一个声音。