Question

我正在尝试制作这个简单的游戏，但我遇到了麻烦。这是代码，它不断循环不同的答案。请原谅这个可怕的故事，请有人帮忙吗？

如果选项等于正确（答案），则代码应该快速。但事实并非如此，它只是在两个选项之间保持循环，直到它击中正确的选项。

import random


def options():
    print()
    print("What do you do?")
    print("1. Check the local bakery to see if the criminal is hiding in the oven.")
    print("2. Search the forest to see if he's made a quick getaway.")
    print("3. Check with the innkeeper to see if anyone has come in recently.")
    print("4. Search the sewers, this criminal scum will do anything for money.")
    print("9. Quit.")



print("On a dark and rainy night the town of Ogalu was quietly sleeping. On this night, a criminal \nwas amidst the sleeping people he sought to steal the King's crown and make himself rich."
        "The criminal named Zalox snuck into the palace, and stole the crown without alerting the guards. \nAfter this he ran away, but you, Bob the guard, heard something. You went to check the king"
        "he was safe, you then went to check the crown. They were gone!, you alert the townsguard and set \nout to catch this criminal scum.")
correct = random.randint(1,4)
options()
option = int(input("What option: "))
while option != 9:
    if option == 1:
        if correct == option:
            print("You make your way into the local bakery, you hear something drop. You turn around and there he is, the theif, in the local oven. You arrest him and put him in jail!")
        else:
            print("As you search the bakery you think you hear something near the oven, as you check it out you realise it's just a mouse. The theif isn't here!")

    elif option == 2:
        if correct == 2:
            print("As you make your way towards the forest you see a shadow limping away, it's the theif! You chase after him and catch him, you send him to jail for life!")
            break
        else:
            print("You head towards the forest, you think you hear something moving in the bushes, as you check it out a giant wolf chases you out of the forest, the theif isn't here")
    elif option == 3:
        if correct == 3:
            print("You approach the innkeeper and ask if anyone suspicious has been staying there, the innkeeper says a man came in recently in a hurry, he's in his room. You dart upstairs, burst into his room"
                    "and arrest him!")
            break
        else:
            print("You see the innkeeper walking his dog, you ask if anyone suspicious has been stayig with him, he says no. The theif isn't here")

    elif option == 4:
        if correct == 4:
            print("You search the old, dirty, smelly sewers looking for the thief, in the distance you see a light and a person running. It's the thief! You take a shortcut and pounce on him! You put him to jail!")
            break
        else:
            print("As you search the sewers you see nothing but smelly, dirty, sewage. Maybe the theif won't do anything for money. This was a bad idea, you make your way out the next exit")

print("Congratulatious! You saved the King's crown by capturing the theif know as Zalox. He's sentanced to life in jail. The town can finally relax again! You are know as Hero of Ogalu!")

Answer 1

您使循环以option的值更改为条件，但仅在循环外指定该名称：

option = int(input("What option: "))
while option != 9:

将其移到while循环中（同时确保option的初始赋值满足while循环的条件！）。

此外，未经请求的建议：一旦你利用dict离子的力量，你将被吹走。这真是太棒了。将这些选择映射到要调用的字符串或对象或函数，它可能更清晰和/或更具可扩展性。

字符串不断重复，直到randint提供正确的答案。

1 个答案: