以下code.Error有什么问题 警告:为foreach()提供的参数无效
if(isset($_POST['submit']))
{
foreach($_POST['team[]'] as $value)
{
$insert=mysql_query("INSERT INTO team('team') VALUES ('$value')");
}
if($insert)
{
echo "dONE";
}
}
<form method="post" action="check.php">
<input type="checkbox" name="team[]" value="AG"> Argentina
<input type="checkbox" name="team[]" value="GE"> Germany
<input type="checkbox" name="team[]" value="BR"> Brazil
<input type="submit" name="submit" value="submit">
</form>
答案 0 :(得分:2)
尝试:
foreach($_POST['team'] as $value)
答案 1 :(得分:1)
不要参考team[]
。而是使用
if (isset($_POST['team'])) {
foreach($_POST['team'] as $value) { ... }
}
答案 2 :(得分:1)
当您从$ _POST接收变量团队时,它将是每个复选框的数组。
因此,您应该使用
而不是team[]
foreach($_POST['team'] as $value)
此外,您应该知道,如果未选中任何复选框,则关键团队将不存在,因此请确保在您的foreach之前执行if (isset($_POST['team']))
你也会在每次循环时覆盖插入。
你可能想做这样的事情:if(isset($_POST['submit']))
{
if (isset($_POST['team']))
{
$insert = true;
foreach($_POST['team'] as $value)
{
// we add security with mysql_real_escape_string
$value = mysql_real_escape_string($value);
$result = mysql_query("INSERT INTO team('team') VALUES ('$value')");
if (!$result)
{
$insert = false;
break;
}
}
if($insert)
{
echo "dONE";
}
}
}
您可能需要检查mysql_real_escape_string以向代码添加secrurity
答案 3 :(得分:0)
当您对输入执行name=something[]
时,php会为您创建数组,因此您只需要这样做
foreach($_POST['team'] as $value)
像name=team[member][]
这样的东西也可以在php中迭代,如此
foreach($_POST['team']['member'] as $value)
因此,它使分组输入和处理多个动态输入变得非常容易
答案 4 :(得分:0)
尝试以下方法:
$teams = $_POST['team'];
$submitted = $_POST['submit'];
if(isset($submitted) && is_array($teams)) {
foreach($teams as $team) {
/* Escapes special characters in a string for use in an SQL statement */
$team = mysql_real_escape_string($team)
$insert = mysql_query("INSERT INTO team('team') VALUES ('$team')");
}
if($insert) {
echo "dONE";
}
} else {
echo "Either Form Not Submitted or Teams is Not Array";
}