我正在尝试学习C并且我编写了一个小程序来计算各种形状的区域。这是源代码:
#include "stdafx.h"
struct entry
{
float x;
float y;
};
void square()
{
printf("\nPlease enter the size of one of the square's sides\n");
struct entry sq;
scanf_s("%f\n", &sq.x);
printf("\nThe area of the square is %.2f\n\n", sq.x * sq.x);
}
void rectangle()
{
printf("\nPlease enter the length and breadth of the rectangle\n");
struct entry rec;
scanf_s("%f\n", &rec.x);
scanf_s("%f\n", &rec.y);
printf("\nThe area of the rectangle is %.2f\n\n", rec.x * rec.y);
}
void triangle()
{
printf("\nPlease enter the width and height of the triangle\n");
struct entry tri;
scanf_s("Width: %f\n", &tri.x);
scanf_s("Height: %f\n", &tri.y);
printf("\nThe area of the triangle is %.2f\n\n", (tri.x * tri.y)/2);
}
void circle()
{
printf("\nPlease enter the radius of the circle\n");
struct entry circ;
scanf_s("%f\n", &circ.x);
printf("\nThe area of the circle is %.2f\n\n", 3.14 * circ.x * circ.x);
}
void main()
{
int input = 0;
do
{
printf("---Area of a Shape---\n\n");
printf("1. Square\n");
printf("2. Rectangle\n");
printf("3. Triangle\n");
printf("4. Circle\n");
printf("5. Exit\n");
printf("\n\n");
printf("Please make a choice\n");
scanf_s("%d", &input);
switch(input)
{
case 1: square();
break;
case 2: rectangle();
break;
case 3: triangle();
break;
case 4: circle();
break;
case 5: printf("\n\nThank you for using this program! Press enter to exit!\n");
break;
default: printf("\nInvalid choice!\n\n");
break;
}
}
while(input != 5);
getchar();
getchar();
}
我对该程序的唯一问题是,在输入边的大小以便计算区域之后,它会在显示答案之前等待我输入另一个数字(进行选择)。我不知道问题出在哪里。我认为在移动到另一个函数之前,C确保它执行手头的整个函数。你能帮我解决一下这个问题吗?感谢。
答案 0 :(得分:7)
采用scanf
格式
scanf_s("%f\n", &rec.x);
'\n'
不代表文字'\n'
,而是代表空白字符的任意序列。因此,scanf_s
调用不会在数字(和空格)之后输入非空格字符后结束[输入可能不会发送到您的程序,直到您在此之后键入换行符]。只需从格式中删除'\n'
即可。