Question

我在Python中格式化一些代码时遇到了困难：我的代码在这里：

keys = ['(Lag)=(\d+\.?\d*)','\t','(Autocorrelation Index): (\d+\.?\d*)',       '(Autocorrelation Index): (\d+\.?\d*)',     '(Semivariance): (\d+\.?\d*)']

import re
string1 = ''.join(open("dummy.txt").readlines())
found = []
for key in keys:
found.extend(re.findall(key, string1))
for result in found:
    print '%s  =  %s' % (result[0],result[1])
raw_input()

到目前为止，我得到了这个输出：

滞后= 1

滞后= 2

滞后= 3

自相关指数= #value

...

...

Semivariance = #value

但我想要的输出是：

 Lag        AutoCorrelation Index   AutoCorrelation Index   Semivariance
  1              #value                   #value               #value
  2              #value                   #value               #value
  3              #value                   #value               #value

如果可以在CSV文件或txt文件中输出，那就太棒了！

我认为这是你应该如何输出循环的一种方式，但我对循环并不是那么好。

我的更新代码（旧版本）

基于@mutzmatron回答

keys = ['(Lag)=(\d+\.?\d*)',
    '(Autocorrelation Index): (\d+\.?\d*)',
    '(Semivariance): (\d+\.?\d*)']

import re
string1 = open("dummy.txt").readlines().join()
found = []
for key in keys:
    found.extend(re.findall(key, string1))
raw_input()
for result in found:
    print '%s  =  %s' % (result[0], result[1])

raw_input()

尚未编译！我正在使用IDLE python 2.6，因为我不知道提示中的pause命令所以不知道错误信息！

原始问题

我是python的新手并且有一个问题。我正在尝试处理一个大文本文件。这只是它的一小部分：

Band: WDRVI20((0.2*b4-b3)/((0.2*b4)+b3))
Basic Statistics:
  Min: -0.963805
  Max: 0.658219
  Mean: 0.094306
  Standard Deviation: 0.131797
Spatial Statistics, ***Lag=1***:
  Total Number of Observations (Pixels): 769995
  Number of Neighboring Pairs: 1538146
  Moran's I:
    ***Autocorrelation Index: 0.8482564597***
    Expected Value, if band is uncorrelated: -0.000001
    Standard Deviation of Expected Value (Normalized): 0.000806
    Standard Deviation of Expected Value (Randomized): 0.000806
    Z Significance Test (Normalized): 1052.029088
    Z Significance Test (Randomized): 1052.034915
  Geary's C:
    ***Autocorrelation Index: 0.1517324729***
    Expected Value, if band is uncorrelated: 1.000000
    Standard Deviation of Expected Value (Normalized): 0.000807
    Standard Deviation of Expected Value (Randomized): 0.000809
    Z Significance Test (Normalized): 1051.414163
    Z Significance Test (Randomized): 1048.752451
  ***Semivariance: 0.0026356529***
Spatial Statistics, Lag=2:
  Total Number of Observations (Pixels): 769995
  Number of Neighboring Pairs: 3068924
  Moran's I:
 Autocorrelation Index: 0.6230691635
   Expected Value, if band is uncorrelated: -0.000001
   Standard Deviation of Expected Value (Normalized): 0.000571
   Standard Deviation of Expected Value (Randomized): 0.000571
 Z Significance Test (Normalized): 1091.521976
 Z Significance Test (Randomized): 1091.528022
  Geary's C:
Autocorrelation Index: 0.3769372504
  Expected Value, if band is uncorrelated: 1.000000
  Standard Deviation of Expected Value (Normalized): 0.000574
  Standard Deviation of Expected Value (Randomized): 0.000587
 Z Significance Test (Normalized): 1085.700399
 Z Significance Test (Randomized): 1061.931158
Semivariance: 0.0065475488

我需要在star ***值（例如：Autocorrelation Index，Semivariance值）之间提取信息并对其进行处理，也可以将其写入不同的文本文件或excel文件。我能这样做吗？非常感谢帮助。

Answer 1

填充您要查找的密钥列表（regular expressions）。例如，

keys = ['(Lag)=(\d+\.?\d*)',
        '(Autocorrelation Index): (\d+\.?\d*)',
        '(Semivariance): (\d+\.?\d*)']

然后使用正则表达式

搜索这些内容

import re
string1 = ''.join(open(FILE).readlines())
found = []
for key in keys:
    found.extend(re.findall(key, string1))

for result in found:
    print '%s  =  %s' % (result[0], result[1])

然后你应该有一个你想要的条目列表，你可以用它来做你需要的东西！

结果：

Lag  =  1
Autocorrelation Index  =  0.8482564597
Autocorrelation Index  =  0.1517324729
Semivariance  =  0.0026356529

<强> CSV

要输出到CSV，请使用csv模块;

import csv
outfile = open('fileout.csv', 'w')
wrt = csv.writer(outfile)
wrt.writerows(found)
outfile.close()

Answer 2

为了按部分格式化数据，也许最容易处理段如下

keys =['(Lag)=(\d+\.?\d*)',
    '(Autocorrelation Index): (\d+\.?\d*)',
    '(Semivariance): (\d+\.?\d*)']

import re
string1 = ''.join(open("dummy.txt").readlines())

sections = string1.split('Spatial Statistics')

output = []
heads = []

for isec, sec in enumerate(sections):
    found = []
    output.append([])
    for key in keys:
        found.extend(re.findall(key, sec))
    for result in found:
        print '%s  =  %s' % (result[0],result[1])
        output[-1].append(result[1])
    if len(found) > 0 & len(heads) == 0:
        heads = [result[0] for result in found]    

fout = open('output.csv', 'w')
wrt = csv.writer(fout)
wrt.writerow(heads)
wrt.writerows(outputs)
fout.close()

如何在Python中格式化输出？

我的更新代码（旧版本）

原始问题

2 个答案: