是否可以使用preg_replace而不是preg_match缩短此代码?
我正在使用它从电子邮件正文中删除引用的文字。 当您回复电子邮件时引用某人时引用的文字。
# Get rid of any quoted text in the email body
# stripSignature removes signatures from the email
# $body is the body of an email (All headers removed)
$body_array = explode("\n", $this->stripSignature($body));
$new_body = "";
foreach($body_array as $key => $value)
{
# Remove hotmail sig
if($value == "_________________________________________________________________")
{
break;
# Original message quote
}
elseif(preg_match("/^-*(.*)Original Message(.*)-*/i",$value,$matches))
{
break;
# Check for date wrote string
}
elseif(preg_match("/^On(.*)wrote:(.*)/i",$value,$matches))
{
break;
# Check for From Name email section
}
elseif(preg_match("/^On(.*)$fromName(.*)/i",$value,$matches))
{
break;
# Check for To Name email section
}
elseif(preg_match("/^On(.*)$toName(.*)/i",$value,$matches))
{
break;
# Check for To Email email section
}
elseif(preg_match("/^(.*)$toEmail(.*)wrote:(.*)/i",$value,$matches))
{
break;
# Check for From Email email section
}
elseif(preg_match("/^(.*)$fromEmail(.*)wrote:(.*)/i",$value,$matches))
{
break;
# Check for quoted ">" section
}
elseif(preg_match("/^>(.*)/i",$value,$matches))
{
break;
# Check for date wrote string with dashes
}
elseif(preg_match("/^---(.*)On(.*)wrote:(.*)/i",$value,$matches))
{
break;
# Add line to body
}
else {
$new_body .= "$value\n";
}
}
这几乎有效,但它保留了第一行“On Mon,Jul 30,2012 at 10:54 PM,Persons Name写道:”
$body = preg_replace('/(^\w.+:\n)?(^>.*(\n|$))+/mi', "", $body);
答案 0 :(得分:0)
这可能是一种更优雅的方式,但这应该有效(假设正则表达式是正确的):
$search = array(
"/^-*.*Original Message.*-*/i",
"/^On.*wrote:.*/i",
"/^On.*$fromName.*/i",
"/^On.*$toName.*/i",
"/^.*$toEmail.*wrote:.*/i",
"/^.*$fromEmail.*wrote:.*/i",
"/^>.*/i",
"/^---.*On.*wrote:.*/i"
);
$body_array = explode("\n", $this->stripSignature($body));
$body = implode("\n", array_filter(preg_replace($search, '', $body_array)));
// or just
$body = str_replace(
array("\0\n", "\n\0"), '', preg_replace($search, "\0", $body)
);
修改:正如指出的那样,在插入模式之前,需要使用other special characters对电子邮件地址中的点(以及可能的preg_quote()
)进行转义。