Question

（编号为2-10的卡的值应分别为2-10.J，Q和K应为10，A应为1或11，具体取决于手的值。）

如何为这些值分配牌组？此外，游戏需要3轮。我这样做的方式只有一轮。如何让游戏进行三次，同时跟踪玩家的赢/输？

有人可以解释一下如何以一种简单的方式做到这一点吗？

Answer 1

这是一个完整的实现

看看手。核心

import random

class Card:
    def __init__(self,rank,suite):        
        self.rank = rank
        self.suite = suite
    def Rank(self):
        return "Ace Two Three Four Five Six Seven Eight Nine Ten Jack Queen King".split()[self.rank]
    def Suite(self):
        return "Hearts Spades Clubs Diamonds".split()[self.suite]
    def __str__(self):
        #print "Get Self:",type(self)
        #print "Dir:",dir(self)
        #return "OF"
        return self.Rank()+" of "+ self.Suite()


class Hand:
    def __init__(self):
        self.cards = []
    def Score(self):
        aces_ct = 0
        score = 0
        for c in self.cards:
            if c.rank == 0:
                aces_ct += 1
                score += 11
            if 0 < c.rank < 9:
                score += c.rank+1
            else:
                score += 10
        while score > 21 and aces_ct > 0:
            score -= 10
            aces_ct -= 1
        return score
    def add(self,card):
        self.cards.append(card)
    def Show(self,show_only=None):
        if not show_only:
            for k in self.cards:
                print "%s"%k
        else:
            if isinstance(show_only,int):
                print "%s"%self.cards[show_only]
            elif isinstance(show_only,(list,tuple)):
                for idx in show_only:
                    print "%s"%self.cards[idx]


class deck:
    def __init__(self):
        self.cards = []
        for i in range(4):
            for j in range(13):
                self.cards.append(Card(j,i))
        random.shuffle(self.cards)
    def shuffle(self):
        random.shuffle(self.cards)
    def pop(self):
        return self.cards.pop()

if __name__ == "__main__":
    d = deck()
    player_hand = Hand()
    dealer_hand = Hand()
    player_hand.add(d.pop())
    dealer_hand.add(d.pop())
    player_hand.add(d.pop())
    dealer_hand.add(d.pop())
    print "Player Score :",player_hand.Score()
    player_hand.Show()
    print "\n\nDealer Score :",dealer_hand.Score()
    dealer_hand.Show()

Answer 2

您可以将汽车表示为元组：表示套装的字符和表示值的数字。我还要为元组添加第三个值，它的二十一点值（例如一个国王和一个女王都算作10）。

card = ('D', 11, 10)  # card is queen of diamonds

你也可以自己上课代表卡片。

class Card(object):
    def __init__(self, suit, number):
        self.suit = suit
        self.number = number
        self.value = (number if 2 <= number <= 9 else 10)

当然，你必须特别考虑王牌的价值。

Answer 3

您应该动态计算总数。此外，您需要某种方式来存储每个玩家的钱。现在，没有办法知道钱的分配，因为你只有一个。

麻烦给牌组的价值

3 个答案: