Question

如何调整此代码以便从生成的列表中删除第一个ul标记？甚至有可能这样做吗？

这将是我想得到的结果：

<ul>  <--remove this initial tag
   <li></li>
   <li></li>
</ul>
<ul>
   <li></li>
   <li></li>
</ul>

列表生成器

 function buildMenu($parent, $menu)
    {
       $menulist = "";
       if (isset($menu['parents'][$parent]))
       {
          $menulist .= "<ul>\n";
           foreach ($menu['parents'][$parent] as $itemId)
           {
              if(!isset($menu['parents'][$itemId]))
              {
                 $menulist .= "   <li><a href='".$menu['items'][$itemId]['menuURL']."'>".$menu['items'][$itemId]['menuName']."</a></li> \n";
              }
              if(isset($menu['parents'][$itemId]))
              {
                 $menulist .= "   <li><a href='".$menu['items'][$itemId]['menuURL']."'>".$menu['items'][$itemId]['menuName']."</a>";
                 $menulist .= buildMenu($itemId, $menu);
                 $menulist .= "</li> \n";
             }
             }
             $menulist .= "</ul> \n";
       }
       return $menulist;
    }?>

Answer 1

设置分隔符。注意$ first添加到函数变量中，然后FALSE表示每次向底部调用

function buildMenu($parent, $menu, $first = TRUE)
{
   $menulist = "";
   if (isset($menu['parents'][$parent]))
   {
       $menulist .= $first ? "" : "<ul>\n";
       foreach ($menu['parents'][$parent] as $itemId)
       {
          if(!isset($menu['parents'][$itemId]))
          {
             $menulist .= "   <li><a href='".$menu['items'][$itemId]['menuURL']."'>".$menu['items'][$itemId]['menuName']."</a></li> \n";
          }
          if(isset($menu['parents'][$itemId]))
          {
             $menulist .= "   <li><a href='".$menu['items'][$itemId]['menuURL']."'>".$menu['items'][$itemId]['menuName']."</a>";
             $menulist .= buildMenu($itemId, $menu, FALSE);
             $menulist .= "</li> \n";
         }
         }
         $menulist .= "</ul> \n";
   }
   return $menulist;
}?>

Answer 2

替换

$menulist .= "<ul>\n";

通过

$menulist .= strlen($menulist) ? "<ul>\n":"";

修改以删除初始ul标记

2 个答案: