Question

我正在尝试学习一些脚本但是我找不到一种功能的解决方案。

基本上我想要评估我的脚本，因为它可能会降低复杂性和行数。

此脚本的目的是从Amazon S3下载随机加密的MySQL备份，恢复转储并运行一些随机的MySQL查询。

我不确定如何通过电子邮件发送printf语句的输出 - 一个用于标题，第二个用于实际数据。我试图格式化输出，所以它看起来像下面但我不得不从循环中排除标题：

Database:   Table:          Entries:                      

database1   random_table        0                             
database2   random_table        0                             
database3   random_table        0
database4   random_table        0

我想在电子邮件中包含此输出，并根据脚本的成功/失败更改电子邮件主题。

如果循环和MySQL查询可能很复杂，我可能会使用很多。

脚本：

#!/usr/bin/env bash

# DB Details:
db_user="user"
db_pass="password"
db_host="localhost"

# Date
date_stamp=$(date +%d%m%Y)

# Initial Setup
data_dir="/tmp/backup"

# Checks
if [ ! -e /usr/bin/s3cmd ]; then
    echo "Required package (http://s3tools.org/s3cmd)"
    exit 2
fi
if [ -e /usr/bin/gpg ]; then

    gpg_key=$(gpg -K | tr -d "{<,>}" | awk '/an@example.com/ { print $4 }')

    if [ "$gpg_key" != "an@example.com" ]; then
        echo "No GPG key"
        exit 2
    fi

else
    echo "No GPG package"
    exit 2
fi

if [ -d $data_dir ]; then
    rm -rf $data_dir/* && chmod 700 $data_dir
else
    mkdir $data_dir && chmod 700 $data_dir
fi

# S3 buckets
bucket_1=s3://test/

# Download backup

for backup in $(s3cmd ls s3://test/ | awk '{ print $2 }')
do
    latest=$(s3cmd ls $backup | awk '{ print $2 }'  | sed -n '$p')
    random=$(s3cmd ls $latest | shuf | awk '{ print $4 }' | sed -n '1p')
    s3cmd get $random $data_dir >/dev/null 2>&1
done

# Decrypting Files
for file in $(ls -A $data_dir)
do
    filename=$(echo $file | sed 's/\.e//')
    gpg --out $data_dir/$filename --decrypt $data_dir/$file >/dev/null 2>&1 && rm -f $data_dir/$file
    if [ $? -eq 0 ]; then

        # Decompressing Files
        bzip2 -d $data_dir/$filename
        if [ $? -ne 0 ]; then
            echo "Decompression Failed!"
        fi
    else
        echo "Decryption Failed!"
        exit 2
    fi
done

# MySQL Restore

printf "%-40s%-30s%-30s\n\n" Database: Table: Entries:

for dump in $(ls -A $data_dir)
do
    mysql -h $db_host -u $db_user -p$db_pass < $data_dir/$dump
    if [ $? -eq 0 ]; then

        # Random DBs query
        db=$(echo $dump | sed 's/\.sql//')
        random_table=$(mysql -h $db_host -u $db_user -p$db_pass $db -e "SHOW TABLES" | grep -v 'Tables' | shuf | sed -n '1p')
        db_entries=$(mysql -h $db_host -u $db_user -p$db_pass $db -e "SELECT * FROM $random_table" | grep -v 'id' | wc -l)

        printf "%-40s%-30s%-30s\n" $db $random_table $db_entries

        mysql -h $db_host -u $db_user -p$db_pass -e "DROP DATABASE $db"     
    else
        echo "The system was unable to restore backups!"
        rm -rf $data_dir
        exit 2
    fi
done

#Remove backups
rm -rf $data_dir

Answer 1

离开循环：

random_tables=$(mysql -h $db_host -u $db_user -p$db_pass $db -e "SHOW TABLES" | grep -v 'Tables')
table_nb=$(wc -l <<<"$random_tables")

并在循环中

random_table=$(sed -n $((RANDOM%table_nb+1))p <<<"$random_tables")

评论$？是&& rm之后执行的最新命令的状态，它不是解密状态

Bash脚本帮助/评估

1 个答案: