我正在尝试将以下内容集成到我的代码中以取消注册phonestatelistener
TelephonyManager mgr = (TelephonyManager) getSystemService(TELEPHONY_SERVICE);
if(mgr != null) {
mgr.listen(phoneStateListener, PhoneStateListener.LISTEN_NONE);
}
我有一个在后台运行的服务,检查一个号码是否在阻止列表中。如果是,则调用PhonestateListener
TelephonyManager mTM = (TelephonyManager)this.getSystemService(Context.TELEPHONY_SERVICE);
mTM.listen(new phoneStateListener(NumberInbound,Msg_to_display,mTM), PhoneStateListener.LISTEN_CALL_STATE);
但是当我从阻止列表中删除一个号码时,我想取消注册phonestatelistner
。取而代之的是phonestatelistener
总是被注册,而我之前删除的msisdn仍被阻止!
phonestatelistner
的代码
class phoneStateListener extends PhoneStateListener {
String inbounda;
int MessagetoDisplay;
String msg;
String reply;
TelephonyManager myt;
MyService calltoService;
boolean mBound = false;
private static final String TAG = "PHONELISTENER";
phoneStateListener(String inbound,int Message,TelephonyManager t) {
inbounda = inbound;
MessagetoDisplay = Message;
myt = t;
}
public void onCallStateChanged(int state, String incomingNumber) {
if(!incomingNumber.equals(inbounda)){
} else {
final String TAG = "Phone call";
ITelephony telephonyService;
//new code
Log.v("Phone State", "state:"+state);
switch (state) {
case TelephonyManager.CALL_STATE_IDLE:
Log.v("Phone State", "incomingNumber:"+incomingNumber+" ended");
break;
case TelephonyManager.CALL_STATE_OFFHOOK:
Log.v("Phone State", "incomingNumber:"+incomingNumber+" picked up");
break;
case TelephonyManager.CALL_STATE_RINGING:
if(inbounda.equalsIgnoreCase(incomingNumber)){
Log.v("ARE THE SAME...............................", "incomingNumber:"+incomingNumber+ "inbound:"+ inbounda + "MSG TO DISPLAY" +msg);
try{
Class c = Class.forName(myt.getClass().getName());
Method m = c.getDeclaredMethod("getITelephony");
m.setAccessible(true);
telephonyService = (ITelephony) m.invoke(myt);
telephonyService.silenceRinger();
telephonyService.endCall();
} catch (Exception e) {
e.printStackTrace();
}
try{
Thread.currentThread().sleep(4000);
replyChecker(MessagetoDisplay);
} catch(InterruptedException ie){
}
}
break;
default:
break;
}
}
}
public String replyChecker(int Check) {
SmsManager mySMS = SmsManager.getDefault();
String destination = inbounda;
//open - to be extended to allow user to define own tailored message
String Meeting = "Sorry I am at a meeting. Graham ";
String Gym = "I am currently at the gym and will respond to you later. Graham ";
String NewYearsEve = "Happy New Year to you and your loved ones. Graham ";
if(Check == 1) {
Log.v("HERE NOW1",":");
reply = Meeting;
mySMS.sendTextMessage(destination, null, Meeting, null, null);
return reply;
} else if (Check == 2) {
Log.v("HERE NOW2",":");
reply = Gym;
mySMS.sendTextMessage(destination, null, Gym, null, null);
return reply;
} else if (Check == 3) {
Log.v("HERE NOW3",":");
reply = NewYearsEve;
mySMS.sendTextMessage(destination, null, NewYearsEve, null, null);
return reply;
}
// TODO Auto-generated method stub
return reply;
}
}
答案 0 :(得分:1)
我的应用程序中有多个活动,我需要一种方法来保持状态,以防手机进入待机状态并在活动之间保持活跃。
当用户使用您的应用程序时,手机不会进入待机状态,并且绝对不会在活动之间,假设任何模糊的内容与正常的应用程序流程相似。设备只会在不活动后入睡,当用户点击某个活动从一个活动移动到下一个活动时,不活动计时器将重置。
如果您希望在屏幕上显示某些活动时保持设备处于唤醒状态,请在某些android:keepScreenOn
上使用View
或setKeepScreenOn()
,这样您就不必弄乱自己的WakeLock
{1}}。
答案 1 :(得分:1)
实际上,我通过在服务中实现广播接收器解决了这个问题。我遇到的问题与PowerManager没有关系,但该服务没有收听来电。
侦听android.intent.action.PHONE_STATE的广播接收器完成了这项工作
谢谢格雷厄姆