我继承了一个架构,因此对那里的内容没有完全的了解/信心。
我有一个带有projectId的项目表。有很多其他表按项目ID引用此表。我想要做的是运行查询来建立:
如果是SQL Server我知道如何查询元数据但我该如何在Oracle中执行此操作?
答案 0 :(得分:22)
1)
select table_name
from all_constraints
where r_constraint_name = [your pk/uk constraint on PROJECTS(id)]
2)
select table_name
from all_tab_columns
where column_name = 'PROJECT_ID'
您可能希望添加包含OWNER列的额外谓词。
此致 罗布。
答案 1 :(得分:18)
确定。这里有一个请求,为您提供引用的表和列:
SELECT
c_list.CONSTRAINT_NAME as NAME,
substr(c_src.COLUMN_NAME, 1, 20) as SRC_COLUMN,
c_dest.TABLE_NAME as DEST_TABLE,
substr(c_dest.COLUMN_NAME, 1, 20) as DEST_COLUMN
FROM ALL_CONSTRAINTS c_list, ALL_CONS_COLUMNS c_src, ALL_CONS_COLUMNS c_dest
WHERE c_list.CONSTRAINT_NAME = c_src.CONSTRAINT_NAME
AND c_list.OWNER = c_src.OWNER
AND c_list.R_CONSTRAINT_NAME = c_dest.CONSTRAINT_NAME
AND c_list.OWNER = c_dest.OWNER
AND c_list.CONSTRAINT_TYPE = 'R'
AND c_src.OWNER = '<your-schema-here>'
AND c_src.TABLE_NAME = '<your-table-here>'
GROUP BY c_list.CONSTRAINT_NAME, c_src.TABLE_NAME,
c_src.COLUMN_NAME, c_dest.TABLE_NAME, c_dest.COLUMN_NAME;
这给你这样的东西:
NAME |SRC_COLUMN |DEST_TABLE | DEST_COLUMN
----------------------|----------------|----------------------|-----------
CFK_RUB_FOR |FOR_URN |T03_FORMAT |FOR_URN
CFK_RUB_RUB |RUB_RUB_URN |T01_RUBRIQUE |RUB_URN
CFK_RUB_SUP |SUP_URN |T01_SUPPORT |SUP_URN
CFK_RUB_PRD |PRD_URN |T05_PRODUIT |PRD_URN
如果结果可用,则可以忘记substr()函数。这不是我的情况。
答案 2 :(得分:1)
1):SELECT * FROM USER_CONSTRAINTS WHERE CONSTRAINT_NAME='R' and R_CONSTRAINT_NAME='xxx'
其中xxx是项目表
上主键约束的名称 2):SELECT * FROM USER_TAB_COLUMNS WHERE COLUMN_NAME='PROJECT_ID'
答案 3 :(得分:0)
这里的r_constraint_name
答案对我来说似乎不起作用,不知道为什么我自己是Oracle的新手,但这很有效:
SELECT * FROM ALL_CONSTRAINTS WHERE CONSTRAINT_NAME = '<constraint>';
答案 4 :(得分:0)
我的问题略有不同。我有一个表,我想以编程方式知道它引用了哪些其他表/列。
我从上面的Stan的回答开始,但这并没有给我我所需要的,所以我提出了这个,我在这里发布以防其他人有我的问题:
WITH src as
(SELECT ac.table_name, ac.constraint_name, accs.column_name, accs.position, ac.r_constraint_name
FROM ALL_CONSTRAINTS ac, all_cons_columns accs
WHERE ac.owner = '<owner>'
AND ac.constraint_type = 'R'
AND ac.table_name = '<src_table>'
AND accs.owner = ac.owner
AND accs.table_name = ac.table_name
AND accs.constraint_name = ac.constraint_name
ORDER BY ac.table_name, ac.constraint_name, accs.position),
dst as
(SELECT ac.table_name, ac.constraint_name, accs.column_name, accs.position
FROM ALL_CONSTRAINTS ac, all_cons_columns accs
WHERE ac.owner = '<owner>'
AND accs.owner = ac.owner
AND accs.table_name = ac.table_name
AND accs.constraint_name = ac.constraint_name
ORDER BY ac.table_name, ac.constraint_name, accs.position)
SELECT src.table_name as src_table,
dst.table_name as dst_table,
src.constraint_name as src_constraint,
src.column_name as src_column,
dst.column_name as dst_column,
src.position as position
FROM src,dst
WHERE src.r_constraint_name = dst.constraint_name
AND src.position = dst.position
答案 5 :(得分:0)
使用此查询。
select b.TABLE_NAME,b.CONSTRAINT_NAME ,a.COLUMN_NAME
from all_constraints b, all_cons_columns a
where r_constraint_name = 'Constraint_Name' and a.CONSTRAINT_NAME=b.CONSTRAINT_NAME;