Question

我不知道为什么，但以下是4小时前返回以下所有日期/时间

function ago($timestamp){
        $difference = floor((time() - strtotime($timestamp))/86400);
        $periods = array("second", "minute", "hour", "day", "week", "month", "years", "decade");
        $lengths = array("60","60","24","7","4.35","12","10");
        for($j = 0; $difference >= $lengths[$j]; $j++)
            $difference /= $lengths[$j];
        $difference = round($difference);
        if($difference != 1)
            $periods[$j].= "s";
        $text = "$difference $periods[$j] ago";
        return $text;
    }

我发送的日期是

 "replydate": "29/07/2012CDT04:54:27",
"replydate": "29/07/2012CDT00:20:10",

Answer 1

功能strtotime不支持此类格式'29/07/2012CDT00:20:10'。使用这样的语法'0000-00-00 00:00:00'。并且不需要86400。所有代码：

function ago($timestamp){
  $difference = time() - strtotime($timestamp);
  $periods = array('second', 'minute', 'hour', 'day', 'week', 'month', 'years', 'decade');
  $lengths = array('60', '60', '24', '7', '4.35', '12', '10');

  for($j = 0; $difference >= $lengths[$j]; $j++) $difference /= $lengths[$j];

  $difference = round($difference);
  if($difference != 1) $periods[$j] .= "s";

  return "$difference $periods[$j] ago";
}

echo ago('2012-7-29 17:20:28');

Answer 2

不如编写自己的日期/时间函数，最好使用像PHP DateTime class这样的标准实现。让时间计算正确有一些微妙之处，例如时区和夏令时。

<?php
    date_default_timezone_set('Australia/Melbourne');

    // Ideally this would use one of the predefined formats like ISO-8601
    //   www.php.net/manual/en/class.datetime.php#datetime.constants.iso8601 
    $replydate_string = "29/07/2012T04:54:27";

    // Parse custom date format similar to original question
    $replydate = DateTime::createFromFormat('d/m/Y\TH:i:s', $replydate_string);

    // Calculate DateInterval (www.php.net/manual/en/class.dateinterval.php)
    $diff = $replydate->diff(new DateTime());

    printf("About %d hour%s and %d minute%s ago\n",
        $diff->h, $diff->h == 1 ? '' : 's',
        $diff->i, $diff->i == 1 ? '' : 's'
    );
?>

PHP时间前函数返回所有日期4小时

2 个答案: