Question

我想创建一个人们必须登录的应用程序，当他们登录时，他们可以从MYSQL数据库中获取自己的个人数据，并将数据显示在UITableView中。

Answer 1

    @implementation FromDataBase

    - (void)viewDidLoad
    {
        [super viewDidLoad];

        //Load Password and Username
        NSUserDefaults *defaults = [NSUserDefaults standardUserDefaults]; 
        LoadUsername = [defaults objectForKey:@"TheUsername"];

        NSUserDefaults *pass = [NSUserDefaults standardUserDefaults]; 
        LoadPassword = [pass objectForKey:@"ThePassword"];


        //Gets the php
        FindURL = [NSString stringWithFormat:@"http://localhost/FromDB/DB.php?username=%@",LoadUsername];
        // to execute php code
        URLData = [NSData dataWithContentsOfURL:[NSURL URLWithString:FindURL]];

        // to receive the returend value
        DataResult = [[NSString alloc] initWithData:URLData encoding:NSUTF8StringEncoding];

        FriendsArray = [DataResult componentsSeparatedByString:@"///"];

        NSLog(@"%@", FriendsArray);

        SearchFriends = [[NSMutableArray alloc] initWithArray:FriendsArray];

    }



    - (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView{
        return 1;
    }
    - (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section{
        return [SearchFriends count];
    }
    - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath{
        UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:@"Cell"];
        if (!cell) {
            cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:@"Cell"];
        }
        cell.textLabel.text = [SearchFriends objectAtIndex:indexPath.row];
        return cell;
    }


    - (void) tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath{

        TheSellected = [SearchFriends objectAtIndex:indexPath.row]; 

        UIAlertView *alert = [[UIAlertView alloc] 
                              initWithTitle:TheSellected
                              message:@"" 
                              delegate:self 
                              cancelButtonTitle:@"OK" 
                              otherButtonTitles:nil, nil];
        [alert show];
        return;


    }
@end

现在PHP：

<?php
if (isset ($_GET["username"]))
        $username = $_GET["username"];
            else{
        $username = "";
            }

//DateBase Infomation
$DB_HostName = "localhost";
$DB_Name = "Users";
$DB_User = "root";
$DB_Pass = "";
$DB_Table = Friends;

//Connecting To Database
$con = mysql_connect($DB_HostName,$DB_User,$DB_Pass);
mysql_select_db($DB_Name,$con);

if(!$con)
{
        die('Connection Failed'.mysql_error());
}


$result = mysql_query("select * from $DB_Table ");


$numrows = mysql_num_rows($result);

if ($numrows!=0){


    while ($row = mysql_fetch_assoc ($result)){
        $Friends = $row['Friends'];
                echo "$Friends///";
    }

}else{
echo "FAILED :(";   
}
?>

我希望这会对你有所帮助:)。

如何从mysql数据库中获取数据并在UITableView中显示它

1 个答案: