Question

我正在尝试构建一个共享库，最终交叉编译一段代码，该代码使用对 be32toh 和 le32toh 的引用。如果我构建这段代码并从中创建一个可执行文件，我就没有错误：

    include $(CLEAR_VARS) 
    LOCAL_SRC_FILES:= ubertooth.c ubertooth_helper.c 
    LOCAL_MODULE := ubertooth 
    LOCAL_C_INCLUDES += jni/libusb jni/libbtbb 
    LOCAL_SHARED_LIBRARIES := libc libusb libbtbb 
    LOCAL_LDLIBS := -L$(SYSROOT)/usr/lib -llog  
    include $(BUILD_EXECUTABLE)

这里成功编译：

    Compile thumb  : ubertooth <= ubertooth.c
    Compile thumb  : ubertooth <= ubertooth_helper.c
    Executable     : ubertooth
    Install        : ubertooth => libs/armeabi/ubertooth

但是，当我尝试仅通过更改 Android.mk 中的一行来将其构建为共享库时：

    include $(CLEAR_VARS) 
    ...
    include $(BUILD_SHARED_LIBRARY)

我现在收到以下错误：

    Compile thumb  : ubertooth <= ubertooth.c
    Compile thumb  : ubertooth <= ubertooth_helper.c
    SharedLibrary  : libubertooth.so
    ./obj/local/armeabi/objs-debug/ubertooth/ubertooth.o: In function `stream_rx_file':
    ubertooth.c:224: undefined reference to `be32toh'
    ./obj/local/armeabi/objs-debug/ubertooth/ubertooth.o: In function `cb_lap':
    ubertooth.c:281: undefined reference to `le32toh'
    ./obj/local/armeabi/objs-debug/ubertooth/ubertooth.o: In function `cb_hop':
    ubertooth.c:417: undefined reference to `le32toh'
    ./obj/local/armeabi/objs-debug/ubertooth/ubertooth.o: In function `cb_btle':
    ubertooth.c:506: undefined reference to `le32toh'
    collect2: ld returned 1 exit status

我不明白为什么在构建共享库时会出现此链接错误，但在构建可执行文件时却不会。而且，如果我想构建共享库，如何正确链接到我缺少的东西？

Here is ubertooth.c

Answer 1

很明显，这些宏在sys / endian.h中的NDK中的命名方式不同：

__uint64_t  htobe64(__uint64_t);
__uint32_t  htobe32(__uint32_t);
__uint16_t  htobe16(__uint16_t);
__uint64_t  betoh64(__uint64_t);
__uint32_t  betoh32(__uint32_t);
__uint16_t  betoh16(__uint16_t);

__uint64_t  htole64(__uint64_t);
__uint32_t  htole32(__uint32_t);
__uint16_t  htole16(__uint16_t);
__uint64_t  letoh64(__uint64_t);
__uint32_t  letoh32(__uint32_t);
__uint16_t  letoh16(__uint16_t);

所以，我用 letoh32 和 betoh32

使用NDK进行交叉编译，对le32toh和be32toh进行未定义的引用

1 个答案: