Question

我想将字符串数组作为参数传递给函数。请看下面的代码

String[] stringArray = {'a', 'b', 'c', 'd', 'e'};

functionFoo(stringArray);

而不是：

functionFoo('a', 'b', 'c', 'd', 'e');

但如果我这样做，则会收到错误消息，指出将String[]转换为String。我想知道是否可以传递这样的值或者正确的方法。

Answer 1

怎么样：

public class test {
    public static void someFunction(String[] strArray) { 
        // do something 
    }

    public static void main(String[] args) {
        String[] strArray = new String[]{"Foo","Bar","Baz"};
        someFunction(strArray);
    }
}

Answer 2

以上所有答案都是正确的。但请注意，当您像这样传递时，您将传递对字符串数组的引用。如果对被调用函数中的数组进行任何修改，它也会反映在调用函数中。

在Java中还有另一个称为变量参数的概念，您可以查看。它基本上是这样的。例如： -

 String concat (String ... strings)
   {
      StringBuilder sb = new StringBuilder ();
      for (int i = 0; i &lt; strings.length; i++)
           sb.append (strings [i]);
      return sb.toString ();
   }

在这里，我们可以像concat（a，b，c，d）或任意数量的参数一样调用函数。

更多信息：http://today.java.net/pub/a/today/2004/04/19/varargs.html

Answer 3

我相信这应该是这样做的方式......

public void function(String [] array){
....
}

呼叫将像......一样完成。

public void test(){
    String[] stringArray = {"a","b","c","d","e","f","g","h","t","k","k","k","l","k"};
    function(stringArray);
}

Answer 4

看一下熟悉的main方法，它将字符串数组作为参数

Answer 5

您的方法声明很可能不正确。确保methods参数的类型为String array（String []），而不仅仅是String，并且在数组声明中使用双引号括起来。

private String[] stringArray = {"a","b","c","d","e","f","g","h","t","k","k","k"};
public void myMethod(String[] myArray) {}

Answer 6

我想您忘记将参数注册为String[]

Answer 7

随意使用这个你喜欢的。

/*
 * The extendStrArray() method will takes a number "n" and
 * a String Array "strArray" and will return a new array
 * containing 'n' new positions. This new returned array
 * can then be assigned to a new array, or the existing
 * one to "extend" it, it contain the old value in the 
 * new array with the addition n empty positions.
 */
private String[] extendStrArray(int n, String[] strArray){
    String[] old_str_array = strArray;
    String[] new_str_array = new String[(old_str_array.length + n)];
    for(int i = 0; i < old_str_array.length; i++ ){
        new_str_array[i] = old_str_array[i];
    }//end for loop

    return new_str_array;

}//end extendStrArray()

基本上我会像这样使用它：

String[] students = {"Tom", "Jeff", "Ashley", "Mary"};
// 4 new students enter the class so we need to extend the string array
students = extendStrArray(4, students); //this will effectively add 4 new empty positions to the "students" array.

Answer 8

请检查以下代码以获取更多详细信息


package FirstTestNgPackage;

import java.util.ArrayList;
import java.util.Arrays;


public class testingclass {

    public static void main(String[] args) throws InterruptedException {
        // TODO Auto-generated method stub
        System.out.println("Hello");
        
        int size = 7;
        String myArray[] = new String[size];
        System.out.println("Enter elements of the array (Strings) :: ");
        for(int i=0; i<size; i++)
        {
        myArray[i] = "testing"+i;
        }
        System.out.println(Arrays.toString(myArray));
        
        
        ArrayList<String> myList = new ArrayList<String>(Arrays.asList(myArray));
        
        
        System.out.println("Enter the element that is to be added:");
        
        myArray = myList.toArray(myArray);
        
        someFunction(myArray);
        }
    
    public static void someFunction(String[] strArray) 
    { 
        System.out.println("in function");
        System.out.println("in function length"+strArray.length );
        System.out.println(Arrays.toString(strArray));
        
           }
        }

只需将其复制并通过...您的代码即可。.然后，您将了解如何将字符串数组作为参数传递...

谢谢

将字符串数组作为参数传递给函数java

8 个答案: