Question

我有一个数据库，并且有多个相同日期和相关金额的记录，但我只想要一条记录，而且与日期相关的总金额

No.       Date                   name   amt
----    -----------------------  -----  ----
4   2012-07-27 10:47:50.000  zerox  15  
5   2012-07-27 12:22:16.000  bag    30  
6   2012-07-28 10:47:50.000  zerox  25  
7   2012-07-28 12:22:16.000  bag    30

我想要这个：

-----------------
date         totamt
----------   -------
2012-07-27   45
2012-07-28   55

Answer 1

select cast([date] as Date) as [Date], 
       sum(amt) TotAmt
from YourTable
group by cast([date] as Date)

Answer 2

假设您的“日期”列没有妨碍，以下情况应该有效。

SELECT
     CAST(date AS DATE),
     SUM(amt) AS totamt
FROM TableName
GROUP BY CAST(date AS DATE)

Answer 3

create table orders(Num int,Date datetime,name varchar(100),amt float)
INSERT INTO orders
VALUES(4,'2012-07-27 10:47:50.000','zerox',15),
(5,'2012-07-27 12:22:16.000','bag',    30),  
(6,'2012-07-28 10:47:50.000','zerox',  25),    
(7,'2012-07-28 12:22:16.000','bag',    30)  

select cast(date as date) date,SUM(amt) sumAmt from orders
group by cast(date as date)

Answer 4

您好试试这个新解决方案：

select convert(varchar,date,101) date,SUM(amt) sumAmt from orders
group by convert(varchar,date,101)

我有一个数据库，以及相同日期和相关金额的多个记录

4 个答案: