我需要将Java类编组并解组为XML。该类不属于我,我无法添加anotations以便我可以使用JAXB。
有没有一种方法可以将Java转换为具有给定约束的XML?
另外,认为一个工具可能会有所帮助,但我会更加感兴趣的是有一些Java API也可以这样做。
答案 0 :(得分:17)
注意:我是EclipseLink JAXB (MOXy)主管,是JAXB (JSR-222)专家组的成员。
DOMAIN MODEL
我将使用以下域模型来获得此答案。请注意模型上没有JAXB注释。
<强> 客户 强>
package forum11693552;
import java.util.*;
public class Customer {
private String firstName;
private String lastName;
private List<PhoneNumber> phoneNumbers = new ArrayList<PhoneNumber>();
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public List<PhoneNumber> getPhoneNumbers() {
return phoneNumbers;
}
public void setPhoneNumbers(List<PhoneNumber> phoneNumbers) {
this.phoneNumbers = phoneNumbers;
}
}
<强> ******中国 强>
package forum11693552;
public class PhoneNumber {
private String type;
private String number;
public String getType() {
return type;
}
public void setType(String type) {
this.type = type;
}
public String getNumber() {
return number;
}
public void setNumber(String number) {
this.number = number;
}
}
选项#1 - 任何JAXB(JSR-222)实施
JAXB是异常配置,这意味着您只需要在希望映射行为与默认值不同的地方添加注释。下面是一个示例的链接,演示如何使用任何没有注释的JAXB impl:
<强> 演示 强>
package forum11693552;
import javax.xml.bind.*;
import javax.xml.namespace.QName;
public class Demo {
public static void main(String[] args) throws Exception {
JAXBContext jc = JAXBContext.newInstance(Customer.class);
Customer customer = new Customer();
customer.setFirstName("Jane");
customer.setLastName("Doe");
PhoneNumber workPhone = new PhoneNumber();
workPhone.setType("work");
workPhone.setNumber("555-1111");
customer.getPhoneNumbers().add(workPhone);
Marshaller marshaller = jc.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
JAXBElement<Customer> rootElement = new JAXBElement<Customer>(new QName("customer"), Customer.class, customer);
marshaller.marshal(rootElement, System.out);
}
}
<强> 输出 强>
<customer>
<firstName>Jane</firstName>
<lastName>Doe</lastName>
<phoneNumbers>
<number>555-1111</number>
<type>work</type>
</phoneNumbers>
</customer>
了解更多信息
选项#2 - EclipseLink JAXB(MOXy)的外部映射文档
如果您确实想要自定义映射,那么您可能对MOXy的外部映射文档扩展感兴趣。示例映射文档如下所示:
<强> oxm.xml 强>
<?xml version="1.0"?>
<xml-bindings xmlns="http://www.eclipse.org/eclipselink/xsds/persistence/oxm"
package-name="forum11693552">
<java-types>
<java-type name="Customer">
<xml-root-element />
<java-attributes>
<xml-element java-attribute="firstName" name="first-name" />
<xml-element java-attribute="lastName" name="last-name" />
<xml-element java-attribute="phoneNumbers" name="phone-number" />
</java-attributes>
</java-type>
<java-type name="PhoneNumber">
<java-attributes>
<xml-attribute java-attribute="type" />
<xml-value java-attribute="number" />
</java-attributes>
</java-type>
</java-types>
</xml-bindings>
<强> jaxb.properties 强>
要启用MOXy作为JAXB提供程序,您需要在与域模型相同的程序包中包含名为jaxb.properties
的文件,并带有以下条目(请参阅:http://blog.bdoughan.com/2011/05/specifying-eclipselink-moxy-as-your.html):
javax.xml.bind.context.factory=org.eclipse.persistence.jaxb.JAXBContextFactory
<强> 演示 强>
当使用EclipseLink MOXy作为JAXB提供程序时(请参阅参考资料),您可以在引导JAXBContext
时利用外部映射文档
package forum11693552;
import java.util.*;
import javax.xml.bind.*;
import javax.xml.namespace.QName;
import org.eclipse.persistence.jaxb.JAXBContextFactory;
public class Demo {
public static void main(String[] args) throws Exception {
Map<String, Object> properties = new HashMap<String,Object>(1);
properties.put(JAXBContextFactory.ECLIPSELINK_OXM_XML_KEY, "forum11693552/oxm.xml");
JAXBContext jc = JAXBContext.newInstance(new Class[] {Customer.class}, properties);
Customer customer = new Customer();
customer.setFirstName("Jane");
customer.setLastName("Doe");
PhoneNumber workPhone = new PhoneNumber();
workPhone.setType("work");
workPhone.setNumber("555-1111");
customer.getPhoneNumbers().add(workPhone);
Marshaller marshaller = jc.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
JAXBElement<Customer> rootElement = new JAXBElement<Customer>(new QName("customer"), Customer.class, customer);
marshaller.marshal(rootElement, System.out);
}
}
<强> 输出 强>
<?xml version="1.0" encoding="UTF-8"?>
<customer>
<first-name>Jane</first-name>
<last-name>Doe</last-name>
<phone-number type="work">555-1111</phone-number>
</customer>
了解更多信息
答案 1 :(得分:5)
你看过XStream了吗?它将对没有注释或XSD的标准POJO进行反序列化/反序列化。您可以提供自定义以影响元素在XML中的显示方式,并且几乎可以开箱即用。
答案 2 :(得分:1)
您可以使用XmlAdapter
注释编写自定义XmlJavaTypeAdapter
并注释约束类型的字段。基础知识将是这样的:
public enum CannotBeAnnotated { value1, value2; }
@XmlRootElement(name="client")
public class ClientClass {
@XmlJavaTypeAdapter(Bridge.class)
public CannotBeAnnotated;
}
@XmlRootElement(name="representation")
public class XmlType {
@XmlValue
public String value;
}
public class Bridge extends XmlAdapter<XmlType, CannotBeAnnotated>{
public XmlType marshal(CannotBeAnnotated c) {
XmlType x=new XmlType();
x.value=c.name();
return x;
}
public CannotBeAnnotated unmarshall(XmlType x) {
return CannotBeAnnotated.valueOf(x.value);
}
}
当然,对于枚举,这不会有用,因为JAXB知道如何处理它们。我刚刚选择了一个简单的枚举,所以你可以看到这个想法:
答案 3 :(得分:0)
您也可以使用JibX