我在PHP中编写了一个简单的搜索脚本。运行时,我得到一个空白屏幕,PHP错误日志状态
绑定变量的数量与预准备语句中的字段数不匹配
我不明白它为什么会这样说,因为我有一个字段与我绑定 - $ searchTitle和一个绑定参数(字符串)。我的标记可能完全错误。
任何建议表示赞赏。感谢。
<?php
if (isset($_POST['btn-search-article'])) {
$searchTitle = $_POST['search-title'];
include_once("mysqli_connect.php");
$table = "articles";
$sql = "SELECT title,
MATCH(title,category,artbody)
AGAINST ('?')
AS score
FROM $table
ORDER BY score DESC";
$stmt = mysqli_stmt_init($dbh);
if (!(mysqli_stmt_prepare($stmt, $sql))) {
echo("Write to DB failed ");
}
else { //statement prepared ok
mysqli_stmt_bind_param($stmt, 's', $searchTitle);
mysqli_stmt_execute($stmt);
mysqli_stmt_bind_result($stmt, $s1);
while (mysqli_stmt_fetch($stmt)) {
echo($s1 . "<br>");
}
mysqli_stmt_close($stmt);
}
} else {
echo("Error: Search could not be completed");
}
?>
注意:PHP错误日志表明错误在行
mysqli_stmt_bind_result($ stmt,$ s1);
FIXED:似乎sql语句的顺序导致了错误。应该是
$sql = "SELECT title
FROM $table
WHERE MATCH (title, category, artbody)
AGAINST (?)";