Question

我在MySQL DB中有以下SQL：

select code, distance from locations;

输出如下：

CODE    DISTANCE            LOCATION
106     386.895834130068    New York, NY
80      2116.6747774121     Washington, DC
80      2117.61925131453    Alexandria, VA
106     2563.46708627407    Charlotte, NC
106     2030.5845606766     Atalanta, GA

我希望能够获得单个代码和最近的距离。所以我希望它能归还：

CODE    DISTANCE            LOCATION
106     386.895834130068    New York, NY
80      2116.6747774121     Washington, DC

我最初有这样的事情：

SELECT code, min(distance), location
GROUP BY code
HAVING distance > 0 
ORDER BY distance ASC

Answer 1

  SELECT code, min(distance), location
GROUP BY code,location
  HAVING distance =min(distance)

Answer 2

试试这个：

select L.* from (
    SELECT code, min(distance) as min_distance 
    from places
    GROUP BY code)a
join places L
on L.CODE=a.CODE
and L.DISTANCE=a.min_distance

Answer 3

SELECT code, distance, location FROM locations GROUP BY code HAVING distance > 0 ORDER BY distance ASC LIMIT 1

MySQL中的SQL Group By和Min

3 个答案: