我已经在android应用程序中开发了一个登录表单,调用mysql数据库调用soap webservices.it在android模拟器上成功运行。但是没有在android真实设备上工作。请问我能做什么。请解释这里发生了什么。
我的android代码是:
package com.androidlogin.ws;
import java.net.SocketException;
import android.util.Log;
import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.PropertyInfo;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapPrimitive;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;
import android.app.Activity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
public class AndroidLoginExampleActivity extends Activity {
private final String NAMESPACE = "http://ws.userlogin.com";
private final String URL = "http://111.223.128.10:8085/AndroidLogin/services/Login?wsdl";
private final String SOAP_ACTION = "http://ws.userlogin.com/authentication";
private final String METHOD_NAME = "authentication";
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Button login = (Button) findViewById(R.id.btn_login);
login.setOnClickListener(new View.OnClickListener() {
public void onClick(View arg0) {
loginAction();
}
});
}
private void loginAction(){
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
EditText userName = (EditText) findViewById(R.id.tf_userName);
String user_Name = userName.getText().toString();
EditText userPassword = (EditText) findViewById(R.id.tf_password);
String user_Password = userPassword.getText().toString();
//Pass value for userName variable of the web service
PropertyInfo unameProp =new PropertyInfo();
unameProp.setName("userName");//Define the variable name in the web service method
unameProp.setValue(user_Name);//set value for userName variable
unameProp.setType(String.class);//Define the type of the variable
request.addProperty(unameProp);//Pass properties to the variable
//Pass value for Password variable of the web service
PropertyInfo passwordProp =new PropertyInfo();
passwordProp.setName("password");
passwordProp.setValue(user_Password);
passwordProp.setType(String.class);
request.addProperty(passwordProp);
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.setOutputSoapObject(request);
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
ServiceConnection connection = getServiceConnection();
connection.connect();
try{
connection.setConnectTimeout(60000);
androidHttpTransport.call(SOAP_ACTION, envelope);
SoapPrimitive response = (SoapPrimitive)envelope.getResponse();
TextView result = (TextView) findViewById(R.id.tv_status);
result.setText(response.toString());
}
catch(SocketException ex)
{
Log.e("Error : " , "Error on soapPrimitiveData() " + ex.getMessage());
ex.printStackTrace();
}
}
protected ServiceConnection getServiceConnection() throws IOException {
return new AndroidServiceConnection(URL);
}
}
在我的退出窗口中显示dis消息: 07-20 04:26:22.728:D / SntpClient(71):请求时间失败:java.net.SocketException:协议不支持的地址族
但是我的ip address.port号码都是正确的。
答案 0 :(得分:0)
尝试将此添加到您的AndroidManifest.xml
:
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
您还需要捕获此异常:
catch(SocketException ex)
{
Log.e("Error : " , "Error on soapPrimitiveData() " + ex.getMessage());
ex.printStackTrace();
}
<强>更新强>
尝试在清单文件中添加以下权限:
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.WAKE_LOCK"/>
<uses-permission android:name="android.permission.CHANGE_WIFI_STATE" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<uses-permission android:name="android.permission.ACCESS_WIFI_STATE" />
修改强>
在try block之前添加几行代码:
ServiceConnection connection = getServiceConnection();
connection.connect();
在try块中,写下:
connection.setConnectTimeout(60000); //put a large value for timeout
创建以下方法:
protected ServiceConnection getServiceConnection() throws IOException {
return new AndroidServiceConnection(url);
}
再次运行代码并立即尝试。