Question

在nodejs中require mongoose Schema的最佳方法是什么？

最初我在app.js文件中有这些内容，但是对于更多模型来说这有点大而且不实用。

现在我想将它们移到models文件夹中并使用Model = require('./models/model')将它们导入app.js

如何获得Model填充实际模型？

（exports = mongoose.model(...)失败并给我一个空白对象; exports.model = mongoose.model(...)要求我做Model.model来访问它 - 这些都不是理想的行为）

===

EDIT1

基本上我已经采取了

var mongoose = require('mongoose');
var Schema = mongoose.Schema, ObjectId = Schema.ObjectId;

var UserSchema = new Schema({
  username: String,
  password: String,
  first_name: String,
  last_name: String,
  email: String
});
User = mongoose.model('User', UserSchema);

并将其放入./models/user.js

我如何得到它相当于在app.js中拥有它？

Answer 1

在app.js服务器文件中，包含如下的model.js文件：

var Model = require('./models/model');  //whatever you want to call it

然后，您可以在服务器文件中实例化它，如下所示：

//Initiate the  Business API endpoints
var model = new Model(mq, siteConf);
model.getUser(id, function() {
    // handle result
});

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然后在你的文件中放入名为model.js的models文件夹（或任何你想要的），你可以这样设置：

var mongoose = require('mongoose'); 

//MongoDB schemas
var Schema = mongoose.Schema;

var User = new Schema({
  username: String,
  password: String,
  first_name: String,
  last_name: String,
  email: String
});
var UserModel = mongoose.model('User', User);

// your other objects defined ...


module.exports = function(mq, siteConf) {
//MongoDB
mongoose.connect(siteConf.mongoDbUrl);


// ------------------------
// READ API
// ------------------------

// Returns a user by ID
function getUser(id, found) {
    console.log("find user by id: " + id);
    UserModel.findById(id, found);
}

// Returns one user matching the given criteria
// mainly used to match against email/login during login
function getUserByCriteria(criteria, found) {
    console.log("find user by criteria: " + JSON.stringify(criteria));
    UserModel.findOne(criteria, found);
}



    // more functions for your app ...



return {
    'getUser': getUser, 
            'getUserByCriteria': getUserByCriteria
   };
};

如何在nodejs中“要求”数据库模式

1 个答案:

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