Python检测警报

Question

我正在尝试让我的python脚本检测页面上的警告框

import urllib2
url = raw_input("Please enter your url: ")
if urllib2.urlopen(url).read().find("<script>alert('alert');</script>") == 0:
    print "Alert Detected!"

如何让它检测警报？

Answer 1

urllib2.urlopen(url).read().find("<script>alert('alert');</script>") == 0来 urllib2.urlopen(url).read().find("<script>alert('alert');</script>") >= 0