我有一些代码从mysql db中提取数据一切都很好,日期,变量等等。我遇到的问题是每次都返回0的唯一整数。
while($row = mysqli_fetch_array($result)) {
$fufilled = "1";
$flag = $row['flag'];
$shopnumb = $row['Shopnumb'];
$shoptype = $row['Shop_type'];
...
$shoptype
和$shopnumb
都返回正确的内容,但$ flag每次都返回0,即使数据库的5行有1,1,1,1,0
CREATE TABLE `Shop_data` (
`Shopnumb` int(15) NOT NULL AUTO_INCREMENT COMMENT 'shop id number',
`flag` tinyint(1) NOT NULL DEFAULT '1' COMMENT '1=unread 0=read',
`CID` int(15) NOT NULL COMMENT 'Client this shop belongs to',
`SID` varchar(50) DEFAULT NULL COMMENT 'identifys which survey to use',
`comp_date` date DEFAULT NULL COMMENT 'Completion Date',
`sched_date` date DEFAULT NULL COMMENT 'Scheduled shop date',
`shop_comp` smallint(1) NOT NULL DEFAULT '0' COMMENT 'shopper submitted report',
`edit_comp` smallint(1) NOT NULL DEFAULT '0' COMMENT 'Report has been edited',
`return_shop` smallint(1) NOT NULL DEFAULT '0' COMMENT 'return report to shopper for editing',
`report_comp` smallint(1) NOT NULL DEFAULT '0' COMMENT 'report ready for client',
`Shop_type` varchar(50) DEFAULT NULL,
`Shoploc` varchar(100) DEFAULT NULL,
`shop_cost` decimal(10,2) DEFAULT NULL COMMENT 'Normal or adjusted cost of shop',
`shop_reimb` decimal(10,2) DEFAULT NULL COMMENT 'Shopper reimburstment cost',
`shop_pay` decimal(10,2) DEFAULT NULL COMMENT 'Total cost',
`shopper_assign` varchar(200) DEFAULT NULL COMMENT 'Identifys which shopper assigned',
PRIMARY KEY (`Shopnumb`),
UNIQUE KEY `Shopnumb` (`Shopnumb`)
) ENGINE=MyISAM AUTO_INCREMENT=2252 DEFAULT CHARSET=latin1
我的查询
SELECT * FROM Shop_data WHERE CID='".$_SESSION['CID']."' AND report_comp='1' AND DATEDIFF(CURDATE(), comp_date) <".$lengthoftime." ORDER BY comp_date DESC;
像我说的那样,除了国旗之外,一切都很好
if statement
if ($flag = '0') {
echo "<td align=\"center\"> </td>";
} else {
echo "<td align=\"center\"> <img align=\"middle\" src=\"/images/flag.png\"> </td>";
}
固定 if($ flag =='0'){
答案 0 :(得分:0)
声明
if ($flag = '0') {
是赋值,并且总是为TRUE(它计算为赋值的值,即字符串)。你需要:
if( ! intval($flag)) {