Question

有没有办法将值传递给派生表查询？

在派生表中，我希望从外部查询中引用值([docSVsys].[sID])。

我收到错误：

消息4104，级别16，状态1，行7多部分标识符 “docSVsys.sID”无法绑定。

是的我知道这个查询可以简化为无循环让游标必须循环并尝试将其转换为如此设置。

select top 10 [docSVsys].[sID], [sI].[count]
from docSVsys 
join 
(
    select count(*) as [count]   
    from docSVenum1 as [sIt]
    where  [sIt].[sID] = [docSVsys].[sID] 
) as [sI] 
on  '1' = '1'
order by [docSVsys].[sID]

Cross apply似乎可以解决问题。它比光标版快1/3。使用交叉申请的真实查询。

SELECT [sO].[sID], [sI].[max], [sI].[avg], [sI].[stdev]
FROM docSVsys as [sO] with (nolock)
cross apply 
( 
    select [sO].[sID], max(list.match) as 'max', avg(list.match) as 'avg', stdev(list.match) as 'stdev'
    from
    (
        select #SampleSet.[sID], [match] = 200 * count(*) / CAST ( #SampleSetSummary.[count] + [sO].[textUniqueWordCount]  as numeric(8,0) ) 
        from #SampleSet with (nolock) 
        join FTSindexWordOnce as [match] with (nolock) -- this is current @sID
            on match.wordID  = #SampleSet.wordID
            and [match].[sID] = [sO].[sID]
        join #SampleSetSummary with (nolock)  -- to get the word count from the sample set
            on #SampleSetSummary.[sID] = #SampleSet.[sID] 
        group by #SampleSet.[sID], #SampleSetSummary.[count] 
    ) as list
    having max(list.match) > 60 
) as [sI]  
where [textUniqueWordCount] is not null and [textUniqueWordCount] > 4 and [sO].[sID] <= 10686
order by [sO].[sID]

Answer 1

你可以用CROSS APPLY而不是JOIN来做你想要的事情：

select top 10 [docSVsys].[sID], [sI].[count] 
from docSVsys  
cross apply 
( 
    select count(*) as [count]    
    from docSVenum1 as [sIt] 
    where  [sIt].[sID] = [docSVsys].[sID]  
) as [sI]  
order by [docSVsys].[sID]

Answer 2

将ID添加到派生表中，然后加入：

select top 10 [docSVsys].[sID], [sI].[count]
from docSVsys 
join 
(
     select [sIt].[sID], count(*) as [count]   
     from docSVenum1 as [sIt]
     group by [sIt].[sID]
) as [sI] 
on [sI].[sID] = [docSVsys].[sID] 
order by [docSVsys].[sID]

将值传递到派生表

2 个答案: